Leap year: Difference between revisions
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=={{header|J}}== |
=={{header|J}}== |
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<lang j>isLeap=: |
<lang j>isLeap=: 0 -/@:= 4 100 400 |/ ]</lang> |
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Example use: |
Example use: |
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Revision as of 21:39, 20 July 2010
You are encouraged to solve this task according to the task description, using any language you may know.
Determine whether a given year is a leap year.
See Also
ActionScript
<lang actionscript>public function isLeapYear(year:int):Boolean {
if (year % 100 == 0) {
return (year % 400 == 0);
}
return (year % 4 == 0);
}</lang>
J
<lang j>isLeap=: 0 -/@:= 4 100 400 |/ ]</lang>
Example use:
<lang> isLeap 1900 1996 1997 2000 0 1 0 1</lang>
Java
<lang java>public static boolean isLeapYear(int year){
if(year % 100 == 0) return year % 400 == 0; return year % 4 == 0;
}</lang>
JavaScript
<lang javascript>function isLeapYear(year) {
if (year % 100 == 0) {
return (year % 400 == 0);
}
return (year % 4 == 0);
}</lang>
PHP
<lang php><?php function isLeapYear(year) {
if (year % 100 == 0) {
return (year % 400 == 0);
}
return (year % 4 == 0);
}</lang>
With date('L'):
<lang php><?php function isLeapYear(year) {
return (date('L', mktime(0, 0, 0, 2, 1, year)) === '1')
}</lang>
Python
<lang python>def is_leap_year(year):
if year % 100 == 0:
return year % 400 == 0
return year % 4 == 0
</lang>
Asking for forgiveness instead of permission:
<lang python>import datetime
def is_leap_year(year):
try:
datetime.date(year, 2, 29)
except ValueError:
return False
return True
</lang>