LU decomposition: Difference between revisions

Racket
(D entry updated)
(Racket)
Line 1,483:
[0.0, 1.0, 0.0, 0.0],
[0.0, 0.0, 0.0, 1.0]]</pre>
 
=={{header|Racket}}==
<lang racket>
#lang racket
(require math)
(define A (matrix
[[1 3 5]
[2 4 7]
[1 1 0]]))
 
(matrix-lu A)
; result:
; (mutable-array #[#[1 0 0]
; #[2 1 0]
; #[1 1 1]])
; (mutable-array #[#[1 3 5]
; #[0 -2 -3]
; #[0 0 -2]])
</lang>
 
=={{header|REXX}}==
Anonymous user