Interactive programming (repl): Difference between revisions
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(not incorrect: the task does not require the use of join-with-separators (and doing so would distract from the purpose of the task)) |
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=={{header|Common Lisp}}== |
=={{header|Common Lisp}}== |
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{{incorrect|Lisp|This is [[String concatenation]], not a String Joining.}} |
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The details of interactive use vary widely between implementations. This example is from [[SBCL]]. <code>*</code> is the prompt. |
The details of interactive use vary widely between implementations. This example is from [[SBCL]]. <code>*</code> is the prompt. |
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=={{header|Haskell}}== |
=={{header|Haskell}}== |
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{{incorrect|Haskell|This is [[String concatenation]], not a String Joining.}} |
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The details of interactive use vary widely between implementations. This example is from [[GHC|GHCi]]. |
The details of interactive use vary widely between implementations. This example is from [[GHC|GHCi]]. |
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Revision as of 02:56, 22 February 2009
You are encouraged to solve this task according to the task description, using any language you may know.
Many languages come with a command line interpreter or shell.
Show how to start the interpreter, then interactively create a function of two strings and a separator that returns the strings separated by two concatenated instances of the separator.
For example, f('Rosetta', 'Code', ':') should return 'Rosetta::Code'
Note: this task is not about creating your own interpreter.
Common Lisp
The details of interactive use vary widely between implementations. This example is from SBCL. * is the prompt.
$ rlwrap sbcl This is SBCL 1.0.25, an implementation of ANSI Common Lisp. More information about SBCL is available at <http://www.sbcl.org/>. ... * (defun f (string-1 string-2 separator) (concatenate 'string string-1 separator separator string-2)) F * (f "Rosetta" "Code" ":") "Rosetta::Code" *
E
<lang sh>$ rune # from an OS shell. On Windows there is also a desktop shortcut.</lang>
"?" and ">" are prompts for input; everything else is output.
<lang e>? def f(string1 :String, string2 :String, separator :String) { > return separator.rjoin(string1, "", string2) > }
- value: <f>
? f("Rosetta", "Code", ":")
- value: "Rosetta::Code"
</lang>
Haskell
The details of interactive use vary widely between implementations. This example is from GHCi.
$ ghci ___ ___ _ / _ \ /\ /\/ __(_) / /_\// /_/ / / | | GHC Interactive, version 6.4.2, for Haskell 98. / /_\\/ __ / /___| | http://www.haskell.org/ghc/ \____/\/ /_/\____/|_| Type :? for help. Loading package base-1.0 ... linking ... done. Prelude> let f as bs sep = as ++ sep ++ sep ++ bs Prelude> f "Rosetta" "Code" ":" "Rosetta::Code"
Python
Start the interpreter by typing python at the command line (or select it from a menu). You get a response showing the version of the interpreter being run before giving an input prompt of three greater-than characters and a space:
<lang python>python Python 2.6.1 (r261:67517, Dec 4 2008, 16:51:00) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> def f(string1, string2, separator): return separator.join([string1, , string2])
>>> f('Rosetta', 'Code', ':') 'Rosetta::Code' >>> </lang>
Ruby
Start the interpreter by typing irb at the command line. You will see an input prompt, which by default is name of this program(name of main object):line number:indent level> :
<lang ruby>$ irb irb(main):001:0> def f(string1, string2, separator) irb(main):002:1> [string1, , string2].join(separator) irb(main):003:1> end => nil irb(main):004:0> f('Rosetta', 'Code', ':') => "Rosetta::Code" irb(main):005:0> </lang>