Integer overflow: Difference between revisions
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→Zilog Z80
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jp pe,ErrorHandler ;pe = parity even, but in this case it represents overflow set</lang>
Like other CPUs, the Z80 has no way of knowing whether a value is intended to be signed or unsigned, and unless you explicitly have a jump, call, or return based on overflow after a calculation, the CPU '''will continue with the wrong result.'''
===Game Boy===
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