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Hash from two arrays: Difference between revisions
Undo revision 8211 by Special:Contributions/RrsVbp (User talk:RrsVbp)
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{{task}}
Using two Arrays of equal length, create a Hash object where the elements from on array (the keys) are linked to the elements of the other (the values)
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end loop;
for I in Key_List'range loop
Ada.Text_Io.Put_Line(To_String(Key_List(I)) & " => " &
To_String(Hash.Element(Key_List(I))));
end loop;
end Hash_Map_Test;
==[[C plus plus|C++]]==
[[Category:C plus plus]]
By strict definition a std::map is not a hash, but it provides the same functionality (but note that some C++ has hash sets too).
'''Compiler:''' g++ 4.0.2
#include <map>
#include <string>
int
main( int argc, char* argv[] )
{
std::string keys[] = { "1", "2", "3" } ;
std::string vals[] = { "a", "b", "c" } ;
std::map< std::string, std::string > hash ;
for( int i = 0 ; i < 3 ; i++ )
{
hash[ keys[i] ] = vals[i] ;
}
}
Alternatively:
#include <map> // for std::map
#include <algorithm> // for std::transform
#include <string> // for std::string
#include <utility> // for std::make_pair
int main()
{
std::string keys[] = { "one", "two", "three" };
std::string vals[] = { "foo", "bar", "baz" };
std::map<std::string, std::string> hash;
std::transform(keys, keys+3,
vals,
std::inserter(hash, hash.end()),
std::make_pair<std::string, std::string>);
}
==[[C sharp|C#]]==
[[Category:C sharp]]
System.Collections.HashTable h = new System.Collections.HashTable();
string[] arg_keys = {"foo","bar","val"};
string[] arg_values = {"little", "miss", "muffet"};
//Some basic error checking
int arg_length = 0;
if ( arg_keys.Length == arg_values.Length ) {
arg_length = arg_keys.Length;
}
for( int i = 0; i < arg_length; i++ ){
h.add( arg_keys[i], arg_values[i] );
}
Alternate way of adding values
for( int i = 0; i < arg_length; i++ ){
h[ arg_keys[i] ] = arg_values[i];
}
==[[D]]==
[[Category:D]]
char[][] keys = ["one", "two", "three"]
int[] values = [1, 2, 3];
int[char[]] hash;
foreach(i,k; keys)
hash[k] = values[i];
==[[E]]==
[[Category:E]]
def keys := ["one", "two", "three"]
def values := [1, 2, 3]
__makeMap.fromColumns(keys, values)
==[[Haskell]]==
[[Category:Haskell]]
'''Interpreter:''' [[GHC|GHCi]] 6.6
import Data.Map
makeMap ks vs = fromList $ zip ks vs
mymap = makeMap ['a','b','c'] [1,2,3]
==[[JavaScript]]==
[[Category:JavaScript]]
var keys = ['a', 'b', 'c'];
var values = [1, 2, 3];
var map = {};
for(var i in keys) {
map[ keys[i] ] = values[i];
}
==[[OCaml]]==
[[Category:OCaml]]
The idiomatic solution uses lists rather than arrays.
let keys = [ "foo"; "bar"; "baz" ]
and vals = [ 16384; 32768; 65536 ]
and hash = Hashtbl.create 0;;
List.iter2 (Hashtbl.add hash) keys vals;;
In the extremely unlikely event that it was actually necessary to use arrays, the solution would become slightly less elegant:
let keys = [| "foo"; "bar"; "baz" |]
and vals = [| 16384; 32768; 65536 |]
and hash = Hashtbl.create 0;;
for i = 0 to Array.length keys - 1 do
Hashtbl.add hash keys.(i) vals.(i)
done;;
In either case, an exception is raised if the inputs are different lengths.
==[[Perl]]==
[[Category:Perl]]
'''Interpreter:''' [[Perl]] 5
use List::MoreUtils qw(zip);
my @keys = qw(a b c);
my @vals = (1, 2, 3);
my %hash = zip @keys, @vals;
Using no modules:
my %hash;
@hash{qw(a b c)} = (1, 2, 3);
==[[PHP]]==
[[Category:PHP]]
PHP 5:
$keys = array('a', 'b', 'c');
$values = array(1, 2, 3);
$hash = array_combine($keys, $values);
PHP 4:
$keys = array('a', 'b', 'c');
$values = array(1, 2, 3);
$hash = array();
for ($idx = 0; $idx < count($keys); $idx++) {
$hash[$keys[$idx]] = $values[$idx];
}
==[[Pop11]]==
[[Category:Pop11]]
vars keys = { 1 a b c};
vars vals = { 2 3 valb valc};
vars i;
;;; Create hash table
vars ht = newmapping([], 500, 0, true);
;;; Loop over input arrays (vectors)
for i from 1 to length(keys) do
vals(i) -> ht(keys(i));
endfor;
==[[Python]]==
[[Category:Python]]
'''Interpreter:''' [[Python]] 2.5
<pre>
keys = ['a', 'b', 'c']
values = [1, 2, 3]
hash = dict(zip(keys, values))
# Lazily:
from itertools import izip
hash = dict(izip(keys, values))
</pre>
==[[Ruby]]==
[[Category:Ruby]]
keys=['hal',666,[1,2,3]]
vals=['ibm','devil',123]
hash = Hash[*keys.zip(vals).flatten]
# now hash => {'hal' => 'ibm', 666 => 'devil', [1,2,3] => 123}
#retrieve the value linked to the key [1,2,3]
puts hash[ [1,2,3] ]
#123
== [[Scala]] ==
[[Category:Scala]]
val keys = Array(1, 2, 3)
val values = Array("A", "B", "C")
val map = Map(keys.zip(values) : _*)
// returns Map(1 -> "A", 2 -> "B", 3 -> "C")
// keys.zip(values) is an array of pairs : Array({1, "A"}, {2, "B"}, {3, "C"})
// Map(...) expects multiple pairs arguments. Syntax ": _*" tells the single argument contains multiple values.
== [[Tcl]] ==
[[Category:Tcl]]
Arrays in Tcl are automatically associative, i.e. there are no "not hashed arrays". If we can take "arrays of equal length" to mean "<i>lists</i> of equal length", then the task might look like this:
set keys [list fred bob joe]
set values [list barber plumber tailor]
array set arr {}
foreach a $keys b $values { set $arr($a) $b }
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