Hash from two arrays

Hash from two arrays
You are encouraged to solve this task according to the task description, using any language you may know.

Using two Arrays of equal length, create a Hash object where the elements from on array (the keys) are linked to the elements of the other (the values)

C++

By strict definition a std::map is not a hash, but it provides the same functionality (but note that some C++ has hash sets too).

Compiler: g++ 4.0.2

#include <map>
#include <string>

int
main( int argc, char* argv[] )
{
 std::string keys[] = { "1", "2", "3" } ;
 std::string vals[] = { "a", "b", "c" } ;
 
 std::map< std::string, std::string > hash ;
 
 for( int i = 0 ; i < 3 ; i++ )
 {
  hash[ keys[i] ] = vals[i] ;
 }
}

Alternatively:

#include <map>       // for std::map
#include <algorithm> // for std::transform
#include <string>    // for std::string
#include <utility>   // for std::make_pair

int main()
{
  std::string keys[] = { "one", "two", "three" };
  std::string vals[] = { "foo", "bar", "baz" };

  std::map<std::string, std::string> hash;

  std::transform(keys, keys+3,
                 vals,
                 std::inserter(hash, hash.end()),
                 std::make_pair<std::string, std::string>);
}

C#

 System.Collections.HashTable h = new System.Collections.HashTable();
 
 string[] arg_keys = {"foo","bar","val"};
 string[] arg_values = {"little", "miss", "muffet"};
   
 //Some basic error checking
 int arg_length = 0;
 if ( arg_keys.Length == arg_values.Length ) {
   arg_length = arg_keys.Length;
 }
 
 for( int i = 0; i < arg_length; i++ ){
   h.add( arg_keys[i], arg_values[i] ); 
 }

Alternate way of adding values

 for( int i = 0; i < arg_length; i++ ){
   h[ arg_keys[i] ] = arg_values[i]; 
 }

D

char[][] keys = ["one", "two", "three"]
int[] values  = [1, 2, 3];

int[char[]] hash;

foreach(i,k; keys)
 hash[k] = values[i];

JavaScript

var keys = ['a', 'b', 'c'];
var values = [1, 2, 3];
var map = {};
for(var i in keys) {
  map[ keys[i] ] = values[i];
}

OCaml

The idiomatic solution uses lists rather than arrays.

 let keys = [ "foo"; "bar"; "baz" ]
 and vals = [ 16384; 32768; 65536 ]
 and hash = Hashtbl.create 0;;

 List.iter2 (Hashtbl.add hash) keys vals;;

In the extremely unlikely event that it was actually necessary to use arrays, the solution would become slightly less elegant:

 let keys = [| "foo"; "bar"; "baz" |]
 and vals = [| 16384; 32768; 65536 |]
 and hash = Hashtbl.create 0;;

 for i = 0 to Array.length keys - 1 do
   Hashtbl.add hash keys.(i) vals.(i)
 done;;

In either case, an exception is raised if the inputs are different lengths.

Perl

Interpreter: Perl 5.8.8

Short

my @keys = ('a', 'b', 'c');
my @vals = (1, 2, 3);
my %hash;
@hash{@keys} = @vals;

Mid Length

my @keys = ('a', 'b', 'c');
my @vals = (1, 2, 3);
my %hash;
$hash{$keys[$_]} = $vals[$_] for (0 .. $#keys);

Long

my @keys = ('a', 'b', 'c');
my @vals = (1, 2, 3);
my %hash;
foreach my $idx (0..$#keys){
  $hash{$keys[$idx]} = $vals[$idx];
}

PHP

[Category:PHP]]

PHP 5:

$keys = array('a', 'b', 'c');
$values = array(1, 2, 3);
$hash = array_combine($keys, $values);

PHP 4:

$keys = array('a', 'b', 'c');
$values = array(1, 2, 3);
$hash = array();
for ($idx = 0; $idx < count($keys); $idx++) {
  $hash[$keys[$idx]] = $values[$idx];
}

Python

Interpreter: Python 2.5

 keys = ['a', 'b', 'c']
 values = [1, 2, 3]
 hash = dict(zip(keys, values))

Ruby

 keys=['hal',666,[1,2,3]]
 vals=['ibm','devil',123]
 hash={}
 keys.zip(vals).each {|key,val| hash[key] = val}
 #hash => {'hal' => 'ibm', 666 => 'devil', [1,2,3] => 123}

 #retrieve the value linked to the key [1,2,3]
 puts hash[ [1,2,3] ]
 #123