Hash from two arrays: Difference between revisions
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Using two Arrays of equal length, create a Hash object where the elements from on array (the keys) are linked to the elements of the other (the values) |
Using two Arrays of equal length, create a Hash object where the elements from on array (the keys) are linked to the elements of the other (the values) |
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==[[C++]]== |
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By strict definition a std::map is not a hash, but it provides the same functionality. |
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#include <map> |
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int |
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main( int argc, char* argv[] ) |
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{ |
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std::string keys[] = { "1", "2", "3" } ; |
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std::string vals[] = { "a", "b", "c" } ; |
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std::map< std::string, std::string > hash ; |
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for( int i = 0 ; i < 3 ; i++ ) |
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{ |
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hash[ keys[i] ] = vals[i] ; |
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} |
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} |
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==[[Perl]]== |
==[[Perl]]== |
Revision as of 03:48, 23 January 2007
Hash from two arrays
You are encouraged to solve this task according to the task description, using any language you may know.
You are encouraged to solve this task according to the task description, using any language you may know.
Using two Arrays of equal length, create a Hash object where the elements from on array (the keys) are linked to the elements of the other (the values)
C++
By strict definition a std::map is not a hash, but it provides the same functionality.
#include <map> int main( int argc, char* argv[] ) { std::string keys[] = { "1", "2", "3" } ; std::string vals[] = { "a", "b", "c" } ; std::map< std::string, std::string > hash ; for( int i = 0 ; i < 3 ; i++ ) { hash[ keys[i] ] = vals[i] ; } }
Perl
Interpreter: Perl 5.8.8
Short
my @keys = ('a', 'b', 'c'); my @vals = (1, 2, 3); my %hash; @hash{@keys} = @vals;
Mid Length
my @keys = ('a', 'b', 'c'); my @vals = (1, 2, 3); my %hash; $hash{$keys[$_]} = $vals[$_] for (0 .. $#keys);
Long
my @keys = ('a', 'b', 'c'); my @vals = (1, 2, 3); my %hash; foreach my $idx (0..$#keys){ $hash{$keys[$idx]} = $vals[$idx]; }
Ruby
keys=['hal',666,[1,2,3]] vals=['ibm','devil',123] hash={} keys.zip(vals).each {|key,val| hash[key] = val} #hash => {'hal' => 'ibm', 666 => 'devil', [1,2,3] => 123}
#retrieve the value linked to the key [1,2,3] puts hash[ [1,2,3] ] #123
C#
System.Collections.HashTable h = new System.Collections.HashTable(); string[] arg_keys = {"foo","bar","val"}; string[] arg_values = {"little", "miss", "muffet"}; //I added this to just have some basic error checking int arg_length = arg_keys.Length == arg_values.Length ? arg_keys.Length : 0; for( int i = 0; i < arg_length; i++ ){ h.add( arg_keys[i], arg_values[i] ); }
Alternate way of adding values
for( int i = 0; i < arg_length; i++ ){ h[ arg_keys[i] ] = arg_values[i]; }
Python
Interpreter: Python 2.5
keys = ['a', 'b', 'c'] values = [1, 2, 3] hash = dict(zip(keys, values))