FizzBuzz/AWK: Difference between revisions

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===Version 1 - regular if / else===

==Version 1 - regular if / else==

~~with linebreaks after each "FizzBuzz":~~

This is the "traditional" approach:

Loop, and modulo-check to see what to print. <br>

Minor tweak: linebreaks after each "FizzBuzz",

to get a more compact output.

<lang AWK># usage: awk -v n=38 -f FizzBuzz.awk

#

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if(!n) n=100

print "# FizzBuzz:"

for (ii=1; ii<=n; ii++)

if (ii % 15 == 0)

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else

{printf "%3d ", ii}

print "\n# Done."

}</lang>

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</pre>

===Version 2 - bash with echo===

==Version 2 - bash with echo==

~~using echo to generate the numbers:~~

Using echo to generate the numbers as input,

so we need no loop inside the script.

Disadvantage: this needs a shell where echo can do this.

<lang AWK>echo {1..100} | awk '

BEGIN {RS=" "}

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'</lang>

===Version 3 - one-liner with seq===

==Version 3 - one-liner with seq==

using bash with seq to generate the input: <~~!-- http: --~~>

As version 2, using bash with seq to generate the input. <br>

Disadvantage: needs external command seq, i.e. only works on unix.

<lang AWK>seq 100 | awk '$0=NR%15?NR%5?NR%3?$0:"Fizz":"Buzz":"FizzBuzz"'</lang>

===Version 4 - no divisions===

==Version 4 - no divisions==

~~awk, using no division & no modulo:~~

All processing is done inside awk,

using no division & no modulo, and instead some counters:

<lang AWK># usage: awk -v n=38 -f fizzbuzzNoDiv.awk

#

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c1++; c3++; c5++; cF++; x=sprintf("%3d ",c1)

if(c3>= 3) { c3=0; x="Fizz " }

if(c5>= 5) { c5=0; x="Buzz " }

if(cF>=15) { cF=0; x="FizzBuzz\n" }

printf(x)

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Same output as version 1.

===Version 5 - no divisions, repeating pattern===

==Version 5 - no divisions, repeating pattern==

~~another solution with no division & no modulo:~~

Another solution with no division & no modulo.

This is inspired by the version "Without Modulus" of Nimrod,

using a precomputed pattern to decide what to print.

<lang AWK># usage: awk -v n=42 -f fizzbuzzRepeatPattern.awk

#