Fivenum: Difference between revisions

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#<bytecode: 0x7fd0db42a7b8>
#<bytecode: 0x7fd0db42a7b8>
#<environment: namespace:stats>
#<environment: namespace:stats>
x <- c(0.14082834, 0.09748790, 1.73131507, 0.87636009, -1.95059594, 0.73438555,-0.03035726, 1.46675970, -0.74621349, -0.72588772, 0.63905160, 0.61501527, -0.98983780, -1.00447874, -0.62759469, 0.66206163, 1.04312009, -0.10305385, 0.75775634, 0.32566578)
> fivenum(rnorm(4))
> fivenum(rnorm(4))
[1] -0.4366061 -0.2225105 0.3213424 0.7110099 0.7709201
[1] -0.4366061 -0.2225105 0.3213424 0.7110099 0.7709201

Revision as of 19:31, 27 February 2018

Fivenum is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Many big data or scientific programs use boxplots to show distributions of data. In addition, sometimes saving large arrays for boxplots can be impractical and use extreme amounts of RAM. It can be useful to save large arrays as arrays with 5 numbers to save memory. For example, the base statistics of the R programming language have implement Tukey's five number summary as the `fivenum` function (cf. Five-number Summary)

Task Description

Given a large array, reduce a large array to five numbers that will have the same boxplot properties as the larger array.

C

Translation of: Kotlin

<lang c>#include <stdio.h>

  1. include <stdlib.h>

double median(double *x, int start, int end_inclusive) {

   int size = end_inclusive - start + 1;
   if (size <= 0) {
       printf("Array slice cannot be empty\n");
       exit(1);
   }
   int m = start + size / 2;
   if (size % 2) return x[m];
   return (x[m - 1] + x[m]) / 2.0;

}

int compare (const void *a, const void *b) {

   double aa = *(double*)a; 
   double bb = *(double*)b;
   if (aa > bb) return 1;
   if (aa < bb) return -1;
   return 0;

}

int fivenum(double *x, double *result, int x_len) {

   int i, m, lower_end;
   for (i = 0; i < x_len; i++) {
       if (x[i] != x[i]) {
          printf("Unable to deal with arrays containing NaN\n\n");
          return 1;
       }
   } 
   qsort(x, x_len, sizeof(double), compare);
   result[0] = x[0];
   result[2] = median(x, 0, x_len - 1);
   result[4] = x[x_len - 1];
   m = x_len / 2;
   lower_end = (x_len % 2) ? m : m - 1;
   result[1] = median(x, 0, lower_end);
   result[3] = median(x, m, x_len - 1);
   return 0;

}

int show(double *result, int places) {

   int i;
   char f[7];
   sprintf(f, "%%.%dlf", places);
   printf("[");
   for (i = 0; i < 5; i++) {     
       printf(f, result[i]);
       if (i < 4) printf(", ");
   }
   printf("]\n\n");

}

int main() {

   double result[5];
   double x1[11] = {15.0, 6.0, 42.0, 41.0, 7.0, 36.0, 49.0, 40.0, 39.0, 47.0, 43.0};
   if (!fivenum(x1, result, 11)) show(result, 1);
   double x2[6] = {36.0, 40.0, 7.0, 39.0, 41.0, 15.0};
   if (!fivenum(x2, result, 6)) show(result, 1);
   double x3[20] = {
        0.14082834,  0.09748790,  1.73131507,  0.87636009, -1.95059594,  0.73438555,
       -0.03035726,  1.46675970, -0.74621349, -0.72588772,  0.63905160,  0.61501527,
       -0.98983780, -1.00447874, -0.62759469,  0.66206163,  1.04312009, -0.10305385,
        0.75775634,  0.32566578
   };
   if (!fivenum(x3, result, 20)) show(result, 9);
   return 0;

}</lang>

Output:
[6.0, 25.5, 40.0, 42.5, 49.0]

[7.0, 15.0, 37.5, 40.0, 41.0]

[-1.950595940, -0.676741205, 0.233247060, 0.746070945, 1.731315070]

Java

Translation of: Kotlin

<lang java>import java.util.Arrays;

public class Fivenum {

   static double median(double[] x, int start, int endInclusive) {
       int size = endInclusive - start + 1;
       if (size <= 0) throw new IllegalArgumentException("Array slice cannot be empty");
       int m = start + size / 2;
       return (size % 2 == 1) ? x[m] : (x[m - 1] + x[m]) / 2.0;
   }
   static double[] fivenum(double[] x) {
       for (Double d : x) {
           if (d.isNaN())
               throw new IllegalArgumentException("Unable to deal with arrays containing NaN");
       }
       double[] result = new double[5];
       Arrays.sort(x);
       result[0] = x[0];
       result[2] = median(x, 0, x.length - 1);
       result[4] = x[x.length - 1];
       int m = x.length / 2;
       int lowerEnd = (x.length % 2 == 1) ? m : m - 1;
       result[1] = median(x, 0, lowerEnd);
       result[3] = median(x, m, x.length - 1);
       return result;
   }
   public static void main(String[] args) {
       double xl[][] = {
           {15.0, 6.0, 42.0, 41.0, 7.0, 36.0, 49.0, 40.0, 39.0, 47.0, 43.0},
           {36.0, 40.0, 7.0, 39.0, 41.0, 15.0},
           {
                0.14082834,  0.09748790,  1.73131507,  0.87636009, -1.95059594,  0.73438555,
               -0.03035726,  1.46675970, -0.74621349, -0.72588772,  0.63905160,  0.61501527,
               -0.98983780, -1.00447874, -0.62759469,  0.66206163,  1.04312009, -0.10305385,
                0.75775634,  0.32566578
           }
       };
       for (double[] x : xl) System.out.printf("%s\n\n", Arrays.toString(fivenum(x)));
   }

}</lang>

Output:
[6.0, 25.5, 40.0, 42.5, 49.0]

[7.0, 15.0, 37.5, 40.0, 41.0]

[-1.95059594, -0.676741205, 0.23324706, 0.746070945, 1.73131507]

Julia

Works with: Julia version 0.6

<lang julia>function mediansorted(x::AbstractVector{T}, i::Integer, l::Integer)::T where T

   len = l - i + 1
   len > zero(len) || throw(ArgumentError("Array slice cannot be empty."))
   mid = i + len ÷ 2
   return isodd(len) ? x[mid] : (x[mid-1] + x[mid]) / 2

end

function fivenum(x::AbstractVector{T}) where T<:AbstractFloat

   r = Vector{T}(5)
   xs = sort(x)
   mid::Int = length(xs) ÷ 2
   lowerend::Int = isodd(length(xs)) ? mid : mid - 1
   r[1] = xs[1]
   r[2] = mediansorted(xs, 1, lowerend)
   r[3] = mediansorted(xs, 1, endof(xs))
   r[4] = mediansorted(xs, mid, endof(xs))
   r[end] = xs[end]
   return r

end

for v in ([15.0, 6.0, 42.0, 41.0, 7.0, 36.0, 49.0, 40.0, 39.0, 47.0, 43.0],

         [36.0, 40.0, 7.0, 39.0, 41.0, 15.0],
         [0.14082834,  0.09748790,  1.73131507,  0.87636009, -1.95059594,  0.73438555,
         -0.03035726,  1.46675970, -0.74621349, -0.72588772,  0.63905160,  0.61501527,
         -0.98983780, -1.00447874, -0.62759469,  0.66206163,  1.04312009, -0.10305385,
          0.75775634,  0.32566578])
   println("# ", v, "\n -> ", fivenum(v))

end</lang>

Output:
# [15.0, 6.0, 42.0, 41.0, 7.0, 36.0, 49.0, 40.0, 39.0, 47.0, 43.0]
 -> [6.0, 15.0, 40.0, 42.0, 49.0]
# [36.0, 40.0, 7.0, 39.0, 41.0, 15.0]
 -> [7.0, 11.0, 37.5, 39.5, 41.0]
# [0.140828, 0.0974879, 1.73132, 0.87636, -1.9506, 0.734386, -0.0303573, 1.46676, -0.746213, -0.725888, 0.639052, 0.615015, -0.989838, -1.00448, -0.627595,0.662062, 1.04312, -0.103054, 0.757756, 0.325666]
 -> [-1.9506, -0.725888, 0.233247, 0.734386, 1.73132]

Kotlin

The following uses Tukey's method for calculating the lower and upper quartiles (or 'hinges') which is what the R function, fivenum, appears to use.

As arrays containing NaNs and nulls cannot really be dealt with in a sensible fashion in Kotlin, they've been excluded altogether. <lang scala>// version 1.2.21

fun median(x: DoubleArray, start: Int, endInclusive: Int): Double {

   val size = endInclusive - start + 1
   require (size > 0) { "Array slice cannot be empty" }
   val m = start + size / 2
   return if (size % 2 == 1) x[m] else (x[m - 1] + x[m]) / 2.0

}

fun fivenum(x: DoubleArray): DoubleArray {

   require(x.none { it.isNaN() }) { "Unable to deal with arrays containing NaN" }
   val result = DoubleArray(5)
   x.sort()
   result[0] = x[0]
   result[2] = median(x, 0, x.size - 1)
   result[4] = x[x.lastIndex]
   val m = x.size / 2
   var lowerEnd = if (x.size % 2 == 1) m else m - 1
   result[1] = median(x, 0, lowerEnd)
   result[3] = median(x, m, x.size - 1)
   return result

}

fun main(args: Array<String>) {

   var xl = listOf(
       doubleArrayOf(15.0, 6.0, 42.0, 41.0, 7.0, 36.0, 49.0, 40.0, 39.0, 47.0, 43.0),
       doubleArrayOf(36.0, 40.0, 7.0, 39.0, 41.0, 15.0),
       doubleArrayOf(
            0.14082834,  0.09748790,  1.73131507,  0.87636009, -1.95059594,  0.73438555,
           -0.03035726,  1.46675970, -0.74621349, -0.72588772,  0.63905160,  0.61501527,
           -0.98983780, -1.00447874, -0.62759469,  0.66206163,  1.04312009, -0.10305385,
            0.75775634,  0.32566578
       )
   )
   xl.forEach { println("${fivenum(it).asList()}\n") }

}</lang>

Output:
[6.0, 25.5, 40.0, 42.5, 49.0]

[7.0, 15.0, 37.5, 40.0, 41.0]

[-1.95059594, -0.676741205, 0.23324706, 0.746070945, 1.73131507]

Perl

Translation of: R
Works with: Perl 5.10

<lang Perl>

  1. !/usr/bin/env perl

use strict; use warnings; use Cwd 'getcwd'; use feature 'say'; my $TOP_DIRECTORY = getcwd(); local $SIG{__WARN__} = sub {#kill the program if there are any warnings my $message = shift; my $fail_filename = "$TOP_DIRECTORY/$0.FAIL"; open my $fh, '>', $fail_filename or die "Can't write $fail_filename: $!"; printf $fh ("$message @ %s\n", getcwd()); close $fh; die "$message\n"; };#http://perlmaven.com/how-to-capture-and-save-warnings-in-perl

use POSIX qw(ceil floor);

sub fivenum { my $array = shift; my @x = sort {$a <=> $b} @{ $array }; printf("There are %u elements.\n", scalar @{ $array }); my $n = scalar @{ $array }; if ($n == 0) { print "no values were entered into fivenum.\n"; die; } my $n4 = floor(($n+3)/2)/2; my @d = (1, $n4, ($n +1)/2, $n+1-$n4, $n);#d <- c(1, n4, (n + 1)/2, n + 1 - n4, n) my (@floor_d, @ceiling_d); foreach my $d (0..4) { $floor_d[$d] = floor($d[$d]); $ceiling_d[$d] = ceil($d[$d]); } my @sum_array; foreach my $e (0..4) { if (not defined $floor_d[$e]) { say "\$floor_d[$e] isn't defined."; die; } if (not defined $ceiling_d[$e]) { say "\$ceiling_d[$e] isn't defined."; die; } if (!defined $x[$floor_d[$e]-1]) { say "\$x[$floor_d[$e-1]-1] isn't defined."; die; } if (!defined $x[$ceiling_d[$e]-1]) { say "\$x[$ceiling_d[$e]-1] isn't defined."; die; } push @sum_array, (0.5 * ($x[$floor_d[$e]-1] + $x[$ceiling_d[$e]-1])); } return @sum_array; }

my @x = qw(0.14082834 0.09748790 1.73131507 0.87636009 -1.95059594 0.73438555 -0.03035726 1.46675970 -0.74621349 -0.72588772 0.63905160 0.61501527

-0.98983780 -1.00447874 -0.62759469  0.66206163  1.04312009 -0.10305385
 0.75775634  0.32566578);

my @y = fivenum(\@x);

say join (',', @y); </lang>

Output:
 -1.95059594,-0.676741205,0.23324706,0.746070945,1.73131507 

Perl 6

Translation of: Perl

<lang perl6>sub fourths ( Int $end ) {

   my $end_22 = $end div 2 / 2;
   return 0, $end_22, $end/2, $end - $end_22, $end;

} sub fivenum ( @nums ) {

   my @x = @nums.sort(+*)
       or die 'Input must have at least one element';
   my @d = fourths(@x.end);
   return ( @x[@d».floor] Z+ @x[@d».ceiling] ) »/» 2;

}

say .&fivenum for [15, 6, 42, 41, 7, 36, 49, 40, 39, 47, 43],

                 [36, 40, 7, 39, 41, 15], [
   0.14082834,  0.09748790,  1.73131507,  0.87636009, -1.95059594,
   0.73438555, -0.03035726,  1.46675970, -0.74621349, -0.72588772,
   0.63905160,  0.61501527, -0.98983780, -1.00447874, -0.62759469,
   0.66206163,  1.04312009, -0.10305385,  0.75775634,  0.32566578,

]; </lang>

Output:
(6 25.5 40 42.5 49)
(7 15 37.5 40 41)
(-1.95059594 -0.676741205 0.23324706 0.746070945 1.73131507)

R

The commented lines are from R source code. This is extremely easy to execute in R.

Notice that this function, being part of the R source code, is covered by the GNU Public License version 2.

<lang R>

  1. > fivenum
  2. function (x, na.rm = TRUE)
  3. {
  4. xna <- is.na(x)
  5. if (any(xna)) {
  6. if (na.rm)
  7. x <- x[!xna]
  8. else return(rep.int(NA, 5))
  9. }
  10. x <- sort(x)
  11. n <- length(x)
  12. if (n == 0)
  13. rep.int(NA, 5)
  14. else {
  15. n4 <- floor((n + 3)/2)/2
  16. d <- c(1, n4, (n + 1)/2, n + 1 - n4, n)
  17. 0.5 * (x[floor(d)] + x[ceiling(d)])
  18. }
  19. }
  20. <bytecode: 0x7fd0db42a7b8>
  21. <environment: namespace:stats>

x <- c(0.14082834, 0.09748790, 1.73131507, 0.87636009, -1.95059594, 0.73438555,-0.03035726, 1.46675970, -0.74621349, -0.72588772, 0.63905160, 0.61501527, -0.98983780, -1.00447874, -0.62759469, 0.66206163, 1.04312009, -0.10305385, 0.75775634, 0.32566578) > fivenum(rnorm(4)) [1] -0.4366061 -0.2225105 0.3213424 0.7110099 0.7709201 </lang>

zkl

Uses GNU GSL library. <lang zkl>var [const] GSL=Import("zklGSL"); // libGSL (GNU Scientific Library) fcn fiveNum(v){ // V is a GSL Vector, --> min, 1st qu, median, 3rd qu, max

  v.sort();
  return(v.min(),v.quantile(0.25),v.median(),v.quantile(0.75),v.max())

}</lang> <lang zkl>fiveNum(GSL.VectorFromData(

  15.0, 6.0, 42.0, 41.0, 7.0, 36.0, 49.0, 40.0, 39.0, 47.0, 43.0)).println();

println(fiveNum(GSL.VectorFromData(36.0, 40.0, 7.0, 39.0, 41.0, 15.0)));

v:=GSL.VectorFromData(

  0.14082834,  0.09748790,  1.73131507,  0.87636009, -1.95059594,  0.73438555,
 -0.03035726,  1.46675970, -0.74621349, -0.72588772,  0.63905160,  0.61501527,
 -0.98983780, -1.00447874, -0.62759469,  0.66206163,  1.04312009, -0.10305385,
  0.75775634,  0.32566578);

println(fiveNum(v));</lang>

Output:
L(6,25.5,40,42.5,49)
L(7,20.25,37.5,39.75,41)
L(-1.9506,-0.652168,0.233247,0.740228,1.73132)