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Five weekends: Difference between revisions
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end /*y*/
say
say 'There were ' haps " occurrence"s(haps)
'of five-weekend months in
no5s=0
do y=yStart to yStop; if yr5.y then iterate /*skip if OK*/
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end /*y*/
say
say "There are " no5s ' year's(no5s),
"that haven't any five─weekend months in year"s(years) yStart'──►'yStop
exit /*stick a fork in it, we're done.*/
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There are five weekends in 2100 October
There were 201 occurrences of five-weekend months in years 1900──►2100
Year 1900 doesn't have any five-weekend months.
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Year 2096 doesn't have any five-weekend months.
There are 29 years that haven't any five─weekend months in years 1900──►2100
</pre>
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