Five weekends: Difference between revisions
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{{Task/realazthat |
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=={{header|Java}}== |
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}} |
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<lang java>import java.util.Calendar; |
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import java.util.GregorianCalendar; |
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public class FiveFSS { |
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//dreizig tage habt september... |
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private static int[] month31 = {Calendar.JANUARY, Calendar.MARCH, Calendar.MAY, |
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Calendar.JULY, Calendar.AUGUST, Calendar.OCTOBER, Calendar.DECEMBER}; |
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public static void main(String[] args){ |
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for(int year = 1900; year <= 2100; year++){ |
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for(int month:month31){ |
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Calendar date = new GregorianCalendar(year, month, 1); |
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if(date.get(Calendar.DAY_OF_WEEK) == Calendar.FRIDAY){ |
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//months are 0-indexed in Calendar |
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System.out.println((date.get(Calendar.MONTH) + 1) + "-" + year); |
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} |
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} |
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} |
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} |
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}</lang> |
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Output (middle results cut out): |
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<pre>3-1901 |
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8-1902 |
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5-1903 |
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1-1904 |
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7-1904 |
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12-1905 |
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3-1907 |
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5-1908 |
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1-1909 |
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10-1909 |
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7-1910 |
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... |
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12-2090 |
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8-2092 |
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5-2093 |
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1-2094 |
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10-2094 |
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7-2095 |
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3-2097 |
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8-2098 |
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5-2099 |
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1-2100 |
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10-2100</pre> |
Revision as of 22:23, 22 October 2010
Five weekends
You are encouraged to solve this task according to the task description, using any language you may know.
You are encouraged to solve this task according to the task description, using any language you may know.
October of 2010 had five Fridays, five Saturdays, and Five Sundays. Write a program to show all months that have this same characteristic from the year 1900 through 2100 (Gregorian calendar).
Java
<lang java>import java.util.Calendar; import java.util.GregorianCalendar;
public class FiveFSS {
//dreizig tage habt september... private static int[] month31 = {Calendar.JANUARY, Calendar.MARCH, Calendar.MAY, Calendar.JULY, Calendar.AUGUST, Calendar.OCTOBER, Calendar.DECEMBER}; public static void main(String[] args){ for(int year = 1900; year <= 2100; year++){ for(int month:month31){ Calendar date = new GregorianCalendar(year, month, 1); if(date.get(Calendar.DAY_OF_WEEK) == Calendar.FRIDAY){ //months are 0-indexed in Calendar System.out.println((date.get(Calendar.MONTH) + 1) + "-" + year); } } } }
}</lang> Output (middle results cut out):
3-1901 8-1902 5-1903 1-1904 7-1904 12-1905 3-1907 5-1908 1-1909 10-1909 7-1910 ... 12-2090 8-2092 5-2093 1-2094 10-2094 7-2095 3-2097 8-2098 5-2099 1-2100 10-2100