Find square difference: Difference between revisions
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(Created page with "{{Draft task}} ;Task:Find an show on this page the least integer number '''n''', where diffrence of '''n*n''' and '''(n-1)*(n-1)''' greater than '''1000''' <br><br> =={{hea...") |
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;Task:Find an show on this page the least integer number '''n''', where diffrence of '''n*n''' and '''(n-1)*(n-1)''' greater than '''1000''' |
;Task:Find an show on this page the least integer number '''n''', where diffrence of '''n*n''' and '''(n-1)*(n-1)''' greater than '''1000''' |
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>br>The result is '''5001''' because '''501*501 - 500*500 = 251001 - 250000 = 1001 > 1000''' |
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Revision as of 16:08, 18 November 2021
Find square difference is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
- Task
- Find an show on this page the least integer number n, where diffrence of n*n and (n-1)*(n-1) greater than 1000
>br>The result is 5001 because 501*501 - 500*500 = 251001 - 250000 = 1001 > 1000
Ring
<lang ring> load "stdlib.ring" see "working..." + nl limit1 = 6000 limit2 = 1000 oldPrime = 0 newPrime = 0
for n = 1 to limit1
newPrime = n*n if newPrime - oldPrime > limit2 see "Latest number is = " + sqrt(newPrime) + nl exit ok oldPrime = n*n
next
see "done..." + nl </lang>
- Output:
working... Latest number is = 501 done...