Find common directory path: Difference between revisions
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Note: The resultant path should be the valid directory <code>'/home/user1/tmp'</code> and not the longest common string <code>'/home/user1/tmp/cove'</code>.<br> |
Note: The resultant path should be the valid directory <code>'/home/user1/tmp'</code> and not the longest common string <code>'/home/user1/tmp/cove'</code>.<br> |
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If your language has a routine that performs this function (even if it does not have a changeable separator character, then mention it as part of the task) |
If your language has a routine that performs this function (even if it does not have a changeable separator character, then mention it as part of the task) |
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=={{header|Oz}}== |
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With a few helper functions, we can express the solution like this in Oz: |
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<lang oz>declare |
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fun {CommonPrefix Sep Paths} |
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fun {GetParts P} {String.tokens P Sep} end |
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Parts = {ZipN {Map Paths GetParts}} |
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EqualParts = {List.takeWhile Parts fun {$ X|Xr} {All Xr {Equals X}} end} |
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in |
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{Join Sep {Map EqualParts Head}} |
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end |
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fun {ZipN Xs} |
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if {Some Xs {Equals nil}} then nil |
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else |
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{Map Xs Head} | {ZipN {Map Xs Tail}} |
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end |
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end |
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fun {Join Sep Xs} |
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{FoldR Xs fun {$ X Z} {Append X Sep|Z} end nil} |
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end |
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fun {Equals C} |
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fun {$ X} X == C end |
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end |
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fun {Head X|_} X end |
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fun {Tail _|Xr} Xr end |
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in |
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{System.showInfo {CommonPrefix &/ |
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["/home/user1/tmp/coverage/test" |
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"/home/user1/tmp/covert/operator" |
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"/home/user1/tmp/coven/members"]}}</lang> |
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=={{header|J}}== |
=={{header|J}}== |
Revision as of 11:19, 24 March 2010
You are encouraged to solve this task according to the task description, using any language you may know.
Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test' '/home/user1/tmp/covert/operator' '/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory '/home/user1/tmp'
and not the longest common string '/home/user1/tmp/cove'
.
If your language has a routine that performs this function (even if it does not have a changeable separator character, then mention it as part of the task)
Oz
With a few helper functions, we can express the solution like this in Oz: <lang oz>declare
fun {CommonPrefix Sep Paths} fun {GetParts P} {String.tokens P Sep} end Parts = {ZipN {Map Paths GetParts}} EqualParts = {List.takeWhile Parts fun {$ X|Xr} {All Xr {Equals X}} end} in {Join Sep {Map EqualParts Head}} end
fun {ZipN Xs} if {Some Xs {Equals nil}} then nil else {Map Xs Head} | {ZipN {Map Xs Tail}} end end
fun {Join Sep Xs} {FoldR Xs fun {$ X Z} {Append X Sep|Z} end nil} end
fun {Equals C} fun {$ X} X == C end end
fun {Head X|_} X end
fun {Tail _|Xr} Xr end
in
{System.showInfo {CommonPrefix &/ ["/home/user1/tmp/coverage/test" "/home/user1/tmp/covert/operator" "/home/user1/tmp/coven/members"]}}</lang>
J
Solution: <lang j>parseDirs =: (PATHSEP_j_&= <;.2 ])@jhostpath getCommonPrefix =: ([: *./\ *./@({. ="1 }.)) ;@# {.
getCommonDirPath=: [: getCommonPrefix parseDirs&></lang>
Example: <lang j> paths=: '/home/user1/tmp/coverage/test';'/home/user1/tmp/covert/operator';'/home/user1/tmp/coven/members'
getCommonPrefix >paths
/home/user1/tmp/cove
getCommonDirPath paths
/home/user1/tmp/</lang>
PureBasic
PureBasic don't have a path comparator directly but instead have powerful string tools.
Simply by checking the catalog names until they mismatch and add up the correct parts, the task is accomplished. <lang PureBasic>Procedure.s CommonPath(Array InPaths.s(1),separator.s="/")
Protected SOut$="" Protected i, j, toggle If ArraySize(InPaths())=0 ProcedureReturn InPaths(0) ; Special case, only one path EndIf Repeat i+1 toggle=#False For j=1 To ArraySize(InPaths()) If (StringField(InPaths(j-1),i,separator)=StringField(InPaths(j),i,separator)) If Not toggle SOut$+StringField(InPaths(j-1),i,separator)+separator toggle=#True EndIf Else ProcedureReturn SOut$ EndIf Next ForEver
EndProcedure</lang>
Example of implementation <lang PureBasic>Dim t.s(2) t(0)="/home/user1/tmp/coverage/test" t(1)="/home/user1/tmp/covert/operator" t(2)="/home/user1/tmp/coven/members"
Debug CommonPath(t(),"/"))</lang>
Python
The Python os.path.commonprefix function is broken as it returns common characters that may not form a valid directory path: <lang python>>>> import os >>> os.path.commonprefix(['/home/user1/tmp/coverage/test', '/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members']) '/home/user1/tmp/cove'</lang>
This result can be fixed: <lang python>>>> def commonprefix(*args, sep='/'): return os.path.commonprefix(*args).rpartition(sep)[0]
>>> commonprefix(['/home/user1/tmp/coverage/test', '/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members']) '/home/user1/tmp'</lang>
But it may be better to not rely on the faulty implementation at all: <lang python>>>> from itertools import takewhile >>> def allnamesequal(name): return all(n==name[0] for n in name[1:])
>>> def commonprefix(paths, sep='/'): bydirectorylevels = zip(*[p.split(sep) for p in paths]) return sep.join(x[0] for x in takewhile(allnamesequal, bydirectorylevels))
>>> commonprefix(['/home/user1/tmp/coverage/test', '/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members']) '/home/user1/tmp'</lang>
Tcl
<lang tcl>package require Tcl 8.5 proc pop {varname} {
upvar 1 $varname var set var [lassign $var head] return $head
}
proc common_prefix {dirs {separator "/"}} {
set parts [split [pop dirs] $separator] while {[llength $dirs]} { set r {} foreach cmp $parts elt [split [pop dirs] $separator] { if {$cmp ne $elt} break lappend r $cmp } set parts $r } return [join $parts $separator]
}</lang>
% common_prefix {/home/user1/tmp/coverage/test /home/user1/tmp/covert/operator /home/user1/tmp/coven/members} /home/user1/tmp