File extension is in extensions list: Difference between revisions
(→{{header|Ruby}}: Added Ruby entry.) |
m (→{{header|ruby}}: Ruby with a capital R) |
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</lang> |
</lang> |
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=={{header| |
=={{header|Ruby}}== |
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<lang ruby>extensions = [".c",".o",""] |
<lang ruby>extensions = [".c",".o",""] |
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["foo.C","foo.zkl","foo","foo."].each{|f| p extensions.include?( File.extname(f).downcase )} |
["foo.C","foo.zkl","foo","foo."].each{|f| p extensions.include?( File.extname(f).downcase )} |
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true |
true |
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true</pre> |
true</pre> |
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=={{header|zkl}}== |
=={{header|zkl}}== |
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<lang zkl>var exts=T(".c",".o",""); |
<lang zkl>var exts=T(".c",".o",""); |
Revision as of 19:30, 11 August 2014
Given a file name and a list of extensions (including the dot), tell whether the file's extension is in the extensions list. The check should be case insensitive. The file might not have an extension.
Haskell
<lang Haskell> import Data.List import qualified Data.Char as Ch
toLower :: String -> String toLower = map Ch.toLower
isExt :: String -> [String] -> Bool isExt filename extensions = any (`elem` (tails . toLower $ filename)) $ map toLower extensions </lang>
The code defining isExt could be done point free: <lang Haskell> isExt filename = any (`elem` (tails . toLower $ filename)) . map toLower </lang>
Overcoming the one-liner urge on behalf of being more comprehensible would give: <lang Haskell> isExt filename extensions = any (`elem` allTails) lowerExtensions
where allTails = tails . toLower $ filename
lowerExtensions = map toLower extensions </lang>
Python
<lang Python> import os
def isExt(filename, extensions):
return os.path.splitext(filename.lower())[-1] in [e.lower() for e in extensions]
</lang>
Scala
<lang Scala> def isExt(fileName: String, extensions: List[String]): Boolean = {
extensions.map { _.toLowerCase }.exists { fileName.toLowerCase endsWith _ }
} </lang>
Ruby
<lang ruby>extensions = [".c",".o",""] ["foo.C","foo.zkl","foo","foo."].each{|f| p extensions.include?( File.extname(f).downcase )} </lang>
- Output:
true false true true
zkl
<lang zkl>var exts=T(".c",".o",""); fcn hasExtension(fname){ exts.holds(File.splitFileName(fname)[3].toLower()) } T("foo.C","foo.zkl","foo","foo.").apply(hasExtension).println();</lang>
- Output:
L(True,False,True,True)