File extension is in extensions list: Difference between revisions

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{{task}}Given a file name and a list of extensions (including the dot), tell whether the file's extension is in the extensions list. The check should be case insensitive. The file might not have an extension.
{{draft task}}Given a file name and a list of extensions (including the dot), tell whether the file's extension is in the extensions list. The check should be case insensitive. The file might not have an extension.


=={{header|Haskell}}==
=={{header|Haskell}}==

Revision as of 17:57, 11 August 2014

File extension is in extensions list is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Given a file name and a list of extensions (including the dot), tell whether the file's extension is in the extensions list. The check should be case insensitive. The file might not have an extension.

Haskell

<lang Haskell> import Data.List import qualified Data.Char as Ch

toLower :: String -> String toLower = map Ch.toLower

isExt :: String -> [String] -> Bool isExt filename extensions = any (`elem` (tails . toLower $ filename)) $ map toLower extensions </lang>

The code defining isExt could be done point free: <lang Haskell> isExt filename = any (`elem` (tails . toLower $ filename)) . map toLower </lang>

Overcoming the one-liner urge on behalf of being more comprehensible would give: <lang Haskell> isExt filename extensions = any (`elem` allTails) lowerExtensions

                           where allTails = tails . toLower $ filename

lowerExtensions = map toLower extensions </lang>


Python

<lang Python> import os

def isExt(filename, extensions):

   return os.path.splitext(filename.lower())[-1] in [e.lower() for e in extensions]

</lang>


Scala

<lang Scala> def isExt(fileName: String, extensions: List[String]): Boolean = {

   extensions.map { _.toLowerCase }.exists { fileName.toLowerCase endsWith _ }

} </lang>

zkl

<lang zkl>var exts=T(".c",".o",""); fcn hasExtension(fname){ exts.holds(File.splitFileName(fname)[3].toLower()) } T("foo.C","foo.zkl","foo","foo.").apply(hasExtension).println();</lang>

Output:
L(True,False,True,True)