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Factors of an integer: Difference between revisions
→{{header|Ruby}}: improvement of the output
(→{{header|Ruby}}: improvement of the output) |
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Line 2,563:
As we only have to loop up to <math>\sqrt{n}</math>, we can write
<lang ruby>class Integer
def factors
1.upto(Math.sqrt(self)).select {|i| (self % i).zero?}.inject([]) do |f, i|
f << self/i unless i == self/i
f << i
end.sort
end
end
[45, 53, 64].each {|n|
{{out}}
<pre>
53 : [1, 53]
64 : [1, 2, 4, 8, 16, 32, 64]</pre>
=={{header|Run BASIC}}==
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