Exponentiation order: Difference between revisions

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This task will demonstrate the order of [[wp:Exponentiation|exponentiation]] &nbsp; <big>('''x<sup>y</sup>''') </big> &nbsp; when there are multiple exponents.
 
(Many programming languages, &nbsp; especially those with extended-precisionextended─precision integer arithmetic, &nbsp; usually support one of <big> <code>**</code>, <code>^</code>, <code>↑</code> </big> or some such for exponentiation.)
 
 
Line 27:
 
 
;Related tasktasks:
* &nbsp; [[Exponentiation_operator|exponentiation operator]]
* Rosetta Code task: &nbsp; [[Arbitrary-precision integers (included)]]
* &nbsp; [[Arbitrary-precision_integers_(included)|arbitrary-precision integers (included)]]
* &nbsp; [[Exponentiation with infix operators in (or operating on) the base]]
<br><br>
 
=={{header|11l}}==
<syntaxhighlight lang="11l">print(5 ^ 3 ^ 2)
print((5 ^ 3) ^ 2)
print(5 ^ (3 ^ 2))</syntaxhighlight>
{{out}}
<pre>
1.95313e+06
15625
1.95313e+06
</pre>
 
=={{header|Action!}}==
There is no power operator in Action! Power function for REAL type is used. But the precision is insufficient.
{{libheader|Action! Tool Kit}}
<syntaxhighlight lang="action!">INCLUDE "D2:REAL.ACT" ;from the Action! Tool Kit
 
PROC Main()
REAL r2,r3,r5,tmp1,tmp2
 
Put(125) PutE() ;clear screen
 
IntToReal(2,r2)
IntToReal(3,r3)
IntToReal(5,r5)
 
PrintE("There is no power operator in Action!")
PrintE("Power function for REAL type is used.")
PrintE("But the precision is insufficient.")
Power(r5,r3,tmp1)
Power(tmp1,r2,tmp2)
Print("(5^3)^2=")
PrintRE(tmp2)
 
Power(r3,r2,tmp1)
Power(r5,tmp1,tmp2)
Print("5^(3^2)=")
PrintRE(tmp2)
RETURN</syntaxhighlight>
{{out}}
[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Exponentiation_order.png Screenshot from Atari 8-bit computer]
<pre>
There is no power operator in Action!
Power function for REAL type is used.
But the precision is insufficient.
(5^3)^2=15624.9977
5^(3^2)=1953124.17
</pre>
 
=={{header|Ada}}==
5**3**2 is not a valid Ada expression. Parenthesis are mandatory.
 
<syntaxhighlight lang="ada">with Ada.Text_IO;
 
procedure Exponentation_Order is
use Ada.Text_IO;
begin
-- Put_Line ("5**3**2 : " & Natural'(5**3**2)'Image);
Put_Line ("(5**3)**2 : " & Natural'((5**3)**2)'Image);
Put_Line ("5**(3**2) : " & Natural'(5**(3**2))'Image);
end Exponentation_Order;</syntaxhighlight>
 
{{out}}
<pre>(5**3)**2 : 15625
5**(3**2) : 1953125</pre>
 
=={{header|ALGOL 68}}==
Algol 68 provides various alternative symbols for the exponentiation operator generally, "**", "^" and "UP" can be used.
<langsyntaxhighlight lang="algol68">print( ( "5**3**2: ", 5**3**2, newline ) );
print( ( "(5**3)**2: ", (5**3)**2, newline ) );
print( ( "5**(3**2): ", 5**(3**2), newline ) )</langsyntaxhighlight>
{{out}}
<pre>
Line 42 ⟶ 109:
5**(3**2): +1953125
</pre>
 
=={{header|ALGOL-M}}==
The eponentiation operator ** in ALGOL-M works only on integer operands.
<syntaxhighlight lang = "ALGOL">
begin
 
write("5**3**2 = ", 5**3**2);
write("(5**3)**2 = ", (5**3)**2);
write("5**(3**2) = ", 5**(3**2));
 
end
</syntaxhighlight>
{{out}}
The third expression results in a value that exceeds the maximum integer value of 16383. Sadly, ALGOL-M emits no warning or error message when this occurs but simply gives the wrong answer.
<pre>
5**3**2 = 15625
(5**3)**2 = 15625
5**(3**2) = -12955
</pre>
 
=={{header|ALGOL W}}==
The Algol W exponentiation operator always produces a real result and requires an integer right operand, hence the round functions in the following.
<syntaxhighlight lang="algolw">begin
write( "5**3**2: ", round( 5 ** 3 ** 2 ) );
write( "(5**3)**2: ", round( ( 5 ** 3 ) ** 2 ) );
write( "5**(3**2): ", round( 5 ** round( 3 ** 2 ) ) )
end.</syntaxhighlight>
{{out}}
<pre>
5**3**2: 15625
(5**3)**2: 15625
5**(3**2): 1953125
</pre>
 
=={{header|APL}}==
APL has no order of precedence other than right-to-left operation. * is the APL exponentiation operator.
<pre>
5*3*2
1953125
(5*3)*2
15625
5*(3*2)
1953125
</pre>
 
=={{header|AppleScript}}==
 
AppleScript's compiler inserts its own parentheses with 5 ^ 3 ^ 2.
 
<syntaxhighlight lang="applescript">set r1 to 5 ^ 3 ^ 2 -- Changes to 5 ^ (3 ^ 2) when compiled.
set r2 to (5 ^ 3) ^ 2
set r3 to 5 ^ (3 ^ 2)
 
return "5 ^ 3 ^ 2 = " & r1 & "
(5 ^ 3) ^ 2 = " & r2 & "
5 ^ (3 ^ 2) = " & r3</syntaxhighlight>
 
{{output}}
<pre>"5 ^ 3 ^ 2 = 1.953125E+6
(5 ^ 3) ^ 2 = 1.5625E+4
5 ^ (3 ^ 2) = 1.953125E+6"</pre>
 
=={{header|Arturo}}==
 
<syntaxhighlight lang="rebol">print 5^3^2
print (5^3)^2
print 5^(3^2)</syntaxhighlight>
 
{{out}}
 
<pre>1953125
15625
1953125</pre>
 
=={{header|AWK}}==
<syntaxhighlight lang="awk">
<lang AWK>
# syntax: GAWK -f EXPONENTIATION_ORDER.AWK
BEGIN {
Line 52 ⟶ 192:
exit(0)
}
</syntaxhighlight>
</lang>
<p>output:</p>
<pre>
Line 60 ⟶ 200:
</pre>
 
=={{header|CBASIC}}==
==={{header|Applesoft BASIC}}===
C does not have an exponentiation operator. The caret operator '^' performs xor bitwise operation in C. The function pow in the standard C Math library takes 2 arguments.
<syntaxhighlight lang="gwbasic">?"5^3^2 = "5 ^ 3 ^ 2 CHR$ (13)"(5^3)^2 = "(5 ^ 3) ^ 2 CHR$ (13)"5^(3^2) = "5 ^ (3 ^ 2);</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125.01</pre>
==={{header|BASIC256}}===
{{works with|QBasic}}
{{works with|FreeBASIC}}
{{works with|True BASIC}}
{{works with|Run BASIC}}
<syntaxhighlight lang="freebasic">print "5^3^2 = "; 5^3^2
print "(5^3)^2 = "; (5^3)^2
print "5^(3^2) = "; 5^(3^2)
end</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|BBC BASIC}}===
Expressions in C are evaluated by RPN. The RPNs of 5^3^2 and 5^(3^2) are the same and thus also their pow expressions.
<syntaxhighlight lang="bbcbasic">PRINT "5^3^2 = "; 5^3^2
<lang C>
PRINT "(5^3)^2 = "; (5^3)^2
/*Abhishek Ghosh, 20th March 2014, Rotterdam*/
PRINT "5^(3^2) = "; 5^(3^2)</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|Chipmunk Basic}}===
{{works with|Chipmunk Basic|3.6.4}}
<syntaxhighlight lang="qbasic">10 print "5^3^2 = "5^3^2
20 print "(5^3)^2 = "(5^3)^2
30 print "5^(3^2) = "5^(3^2)</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|GW-BASIC}}===
{{works with|Applesoft BASIC}}
{{works with|Chipmunk Basic}}
{{works with|MSX_BASIC}}
{{works with|PC-BASIC|any}}
{{works with|QBasic}}
<syntaxhighlight lang="qbasic">10 PRINT "5^3^2 =" 5^3^2
20 PRINT "(5^3)^2 =" (5^3)^2
30 PRINT "5^(3^2) =" 5^(3^2)</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|IS-BASIC}}===
<syntaxhighlight lang="is-basic">100 PRINT "5^3^2 =";5^3^2
110 PRINT "(5^3)^2 =";(5^3)^2
120 PRINT "5^(3^2) =";5^(3^2)</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|MSX Basic}}===
<syntaxhighlight lang="qbasic">10 PRINT "5^3^2 =" 5^3^2
20 PRINT "(5^3)^2 =" (5^3)^2
30 PRINT "5^(3^2) =" 5^(3^2)</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|PureBasic}}===
In the PureBasic it is impossible to show the result of: 5^3^2
<syntaxhighlight lang="vb">OpenConsole()
PrintN("(5^3)^2 = " + Str(Pow(Pow(5, 3), 2)))
PrintN("5^(3^2) = " + Str(Pow(5, (Pow(3, 2)))))
CloseConsole()</syntaxhighlight>
{{out}}
<pre>(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|QBasic}}===
{{works with|QBasic|1.1}}
{{works with|QuickBasic|4.5}}
{{works with|FreeBASIC}}
{{works with|True BASIC}}
{{works with|BASIC256}}
{{works with|Run BASIC}}
<syntaxhighlight lang="qbasic">PRINT "5^3^2 ="; 5^3^2
PRINT "(5^3)^2 ="; (5^3)^2
PRINT "5^(3^2) ="; 5^(3^2)
END</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|Run BASIC}}===
{{works with|QBasic}}
{{works with|FreeBASIC}}
{{works with|True BASIC}}
{{works with|BASIC256}}
<syntaxhighlight lang="freebasic">print "5^3^2 = "; 5^3^2
print "(5^3)^2 = "; (5^3)^2
print "5^(3^2) = "; 5^(3^2)
end</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|True BASIC}}===
{{works with|QBasic}}
{{works with|FreeBASIC}}
{{works with|BASIC256}}
{{works with|Run BASIC}}
<syntaxhighlight lang="qbasic">PRINT "5^3^2 ="; 5^3^2
PRINT "(5^3)^2 ="; (5^3)^2
PRINT "5^(3^2) ="; 5^(3^2)
END</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|XBasic}}===
{{works with|Windows XBasic}}
<syntaxhighlight lang="qbasic">PROGRAM "Exponentiation order"
VERSION "0.0000"
 
DECLARE FUNCTION Entry ()
 
FUNCTION Entry ()
PRINT "5^3^2 ="; 5**3**2
PRINT "(5^3)^2 ="; (5**3)**2
PRINT "5^(3^2) ="; 5**(3**2)
END FUNCTION
END PROGRAM</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|Yabasic}}===
{{works with|QBasic}}
{{works with|FreeBASIC}}
{{works with|True BASIC}}
{{works with|BASIC256}}
<syntaxhighlight lang="freebasic">print "5^3^2 = ", 5^3^2
print "(5^3)^2 = ", (5^3)^2
print "5^(3^2) = ", 5^(3^2)
end</syntaxhighlight>
{{out}}
<pre>5^3^2 = 15625
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
==={{header|Sinclair ZX81 BASIC}}===
<syntaxhighlight lang="basic">10 PRINT "5**3**2 = ";5**3**2
20 PRINT "(5**3)**2 = ";(5**3)**2
30 PRINT "5**(3**2) = ";5**(3**2)</syntaxhighlight>
{{out}}
<pre>5**3**2 = 15625
(5**3)**2 = 15625
5**(3**2) = 1953125</pre>
 
=={{header|Bracmat}}==
<syntaxhighlight lang="bracmat">put$str$("5^3^2: " 5^3^2 "\n(5^3)^2: " (5^3)^2 "\n5^(3^2): " 5^(3^2) \n) </syntaxhighlight>
{{out}}
<pre>5^3^2: 1953125
(5^3)^2: 15625
5^(3^2): 1953125</pre>
 
=={{header|C}}==
C does not have an exponentiation operator. The caret operator '^' performs xor bitwise operation in C. The function pow in the standard C Math library takes two arguments.
 
<syntaxhighlight lang="c">#include<stdio.h>
#include<math.h>
 
int main()
{
printf("\n5(5 ^ 3) ^ 2 = %.0f",pow(pow(5,pow(3),2))); /*.0f suppresses decimal output*/
printf("\n(5n5 ^ (3) ^ 2) = %.0f",pow(pow(5,pow(3),2)));
printf("\n5 ^ (3 ^ 2) = %.0f",pow(5,pow(3,2)));
return 0;
}</syntaxhighlight>
}
 
</lang>
{{out}}
<pre>
(5 ^ 3) ^ 2 = 15625
5 ^ (3 ^ 2) = 1953125
</pre>
 
=={{header|C++}}==
5 ^ 3 ^ 2 = 1953125
<syntaxhighlight lang="cpp">#include <iostream>
#include <cmath>
 
int main() {
std::cout << "(5 ^ 3) ^ 2 = " << (uint) pow(pow(5,3), 2) << std::endl;
std::cout << "5 ^ (3 ^ 2) = "<< (uint) pow(5, (pow(3, 2)));
return EXIT_SUCCESS;
}</syntaxhighlight>
 
With permissive flag:
<syntaxhighlight lang="cpp">#include <iostream>
#include <cmath>
 
enum my_int {};
inline my_int operator^(my_int a, my_int b) { return static_cast<my_int>(pow(a,b)); }
 
int main() {
my_int x = 5, y = 3, z = 2;
std::cout << "(5 ^ 3) ^ 2 = " << ((x^y)^z) << std::endl;
std::cout << "5 ^ (3 ^ 2) = "<< (x^(y^z));
return EXIT_SUCCESS;
}</syntaxhighlight>
 
{{out}}
<pre>
(5 ^ 3) ^ 2 = 15625
5 ^ (3 ^ 2) = 1953125
</pre>
 
=={{header|C sharp|C#}}==
<syntaxhighlight lang="csharp">using System;
 
namespace exponents
{
class Program
{
static void Main(string[] args)
{
/*
* Like C, C# does not have an exponent operator.
* Exponentiation is done via Math.Pow, which
* only takes two arguments
*/
Console.WriteLine(Math.Pow(Math.Pow(5, 3), 2));
Console.WriteLine(Math.Pow(5, Math.Pow(3, 2)));
Console.Read();
}
 
}
}
</syntaxhighlight>
{{out}}
<pre>
15625
1953125
</pre>
 
Line 90 ⟶ 457:
Clojure uses prefix notation and expt only takes 2 arguments for exponentiation, so "5**3**2" isn't represented.
 
<langsyntaxhighlight lang="clojure">(use 'clojure.math.numeric-tower)
;; (5**3)**2
(expt (expt 5 3) 2) ; => 15625
Line 102 ⟶ 469:
;; 5**(3**2) alternative: evaluating right-to-left with reduce requires a small modification
(defn rreduce [f coll] (reduce #(f %2 %) (reverse coll)))
(rreduce expt [5 3 2]) ; => 1953125</langsyntaxhighlight>
 
=={{header|CLU}}==
<syntaxhighlight lang="clu">start_up = proc ()
po: stream := stream$primary_output()
stream$putl(po, "5**3**2 = " || int$unparse(5**3**2))
stream$putl(po, "(5**3)**2 = " || int$unparse((5**3)**2))
stream$putl(po, "5**(3**2) = " || int$unparse(5**(3**2)))
end start_up</syntaxhighlight>
{{out}}
<pre>5**3**2 = 1953125
(5**3)**2 = 15625
5**(3**2) = 1953125</pre>
 
=={{header|Common Lisp}}==
Because Common Lisp uses prefix notation and <code>expt</code> accepts only two arguments, it doesn't have an expression for <code>5**3**2</code>. Just showing expressions for the latter two.
<syntaxhighlight lang="lisp">(expt (expt 5 3) 2)
(expt 5 (expt 3 2))</syntaxhighlight>
{{out}}
<pre>15625
1953125</pre>
 
=={{header|D}}==
<langsyntaxhighlight lang="d">void main() {
import std.stdio, std.math, std.algorithm;
 
Line 112 ⟶ 500:
writefln("5 ^^ (3 ^^ 2) = %7d", 5 ^^ (3 ^^ 2));
writefln("[5, 3, 2].reduce!pow = %7d", [5, 3, 2].reduce!pow);
}</langsyntaxhighlight>
{{out}}
<pre>5 ^^ 3 ^^ 2 = 1953125
Line 118 ⟶ 506:
5 ^^ (3 ^^ 2) = 1953125
[5, 3, 2].reduce!pow = 15625</pre>
 
=={{header|Delphi}}==
{{works with|Delphi|6.0}}
{{libheader|Math,SysUtils,StdCtrls}}
Delphi doesn't have exponentiation but it does have the "Power" function in the math library
 
<syntaxhighlight lang="Delphi">
procedure ExponentDemo(Memo: TMemo);
begin
Memo.Lines.Add('5^3^2 = '+FloatToStrF(Power(5,Power(3,2)),ffNumber,18,0));
Memo.Lines.Add('(5^3)^2 = '+FloatToStrF(Power(Power(5,3),2),ffNumber,18,0));
Memo.Lines.Add('5^(3^2) = '+FloatToStrF(Power(5,Power(3,2)),ffNumber,18,0));
end;
 
 
</syntaxhighlight>
{{out}}
<pre>
5^3^2 = 1,953,125
(5^3)^2 = 15,625
5^(3^2) = 1,953,125
 
</pre>
 
=={{header|Dart}}==
<syntaxhighlight lang="dart">import 'dart:math' show pow;
 
void main() {
print('(5 ^ 3) ^ 2 = ${pow(pow(5, 3), 2)}');
print('5 ^ (3 ^ 2) = ${pow(5, (pow(3, 2)))}');
}</syntaxhighlight>
{{out}}
<pre>(5 ^ 3) ^ 2 = 15625
5 ^ (3 ^ 2) = 1953125</pre>
 
=={{header|EasyLang}}==
<syntaxhighlight>
print "(5 ^ 3) ^ 2 = " & pow (pow 5 3) 2
print "5 ^ (3 ^ 2) = " & pow 5 pow 3 2
</syntaxhighlight>
 
=={{header|EchoLisp}}==
<langsyntaxhighlight lang="scheme">
;; the standard and secure way is to use the (expt a b) function
(expt 5 (expt 3 2)) ;; 5 ** ( 3 ** 2)
Line 137 ⟶ 565:
(5 ** (3 ** 2))
→ 1953125
</syntaxhighlight>
</lang>
 
=={{header|Factor}}==
Factor is a stack language where expressions take the form of reverse Polish notation, so there is no ambiguity here. It is up to you, the programmer, to perform operations in the order you intend.
<syntaxhighlight lang="factor">USING: formatting math.functions ;
 
5 3 2 ^ ^
"5 3 2 ^ ^ %d\n" printf
 
5 3 ^ 2 ^
"5 3 ^ 2 ^ %d\n" printf</syntaxhighlight>
{{out}}
<pre>
5 3 2 ^ ^ 1953125
5 3 ^ 2 ^ 15625
</pre>
 
Factor also has syntax for infix arithmetic via the the <code>infix</code> vocabulary.
 
<syntaxhighlight lang="factor">USING: formatting infix ;
 
[infix 5**3**2 infix]
"5**3**2 = %d\n" printf
 
[infix (5**3)**2 infix]
"(5**3)**2 = %d\n" printf
 
[infix 5**(3**2) infix]
"5**(3**2) = %d\n" printf</syntaxhighlight>
{{out}}
<pre>
5**3**2 = 15625
(5**3)**2 = 15625
5**(3**2) = 1953125
</pre>
 
=={{header|Fortran}}==
<langsyntaxhighlight Fortranlang="fortran">write(*, "(a, i0)") "5**3**2 = ", 5**3**2
write(*, "(a, i0)") "(5**3)**2 = ", (5**3)**2
write(*, "(a, i0)") "5**(3**2) = ", 5**(3**2)</langsyntaxhighlight>
{{out}}
<pre>5**3**2 = 1953125
Line 149 ⟶ 611:
 
=={{header|FreeBASIC}}==
<langsyntaxhighlight lang="freebasic">' FB 1.05.0
 
' The exponentation operator in FB is ^ rather than **.
Line 159 ⟶ 621:
Print "(5^3)^2 =>"; (5^3)^2
Print "5^(3^2) =>"; 5^(3^2)
Sleep</langsyntaxhighlight>
 
{{out}}
Line 167 ⟶ 629:
5^(3^2) => 1953125
</pre>
 
=={{header|Frink}}==
Frink correctly follows standard mathematical notation that exponent towers are performed from "top to bottom" or "right to left."
 
<syntaxhighlight lang="frink">println["5^3^2 = " + 5^3^2]
println["(5^3)^2 = " + (5^3)^2]
println["5^(3^2) = " + 5^(3^2)]
</syntaxhighlight>
 
{{out}}
<pre>
5^3^2 = 1953125
(5^3)^2 = 15625
5^(3^2) = 1953125
</pre>
 
=={{header|FutureBasic}}==
FB is translated into C which does not have an exponentiation operator. The caret operator '^' performs xor bitwise operation. FB also has an fn pow function, translated from the the standard C Math library, which takes two arguments.
<syntaxhighlight lang="futurebasic">
print "(5^3)^2 = "; (5^3)^2
print "5^(3^2) = "; 5^(3^2)
print
print "fn pow( fn pow(5,3), 2 ) = "; fn pow( fn pow(5,3), 2 )
print "fn pow( 5, fn pow(3,2 ) ) = "; fn pow( 5, fn pow(3,2 ) )
 
HandleEvents
</syntaxhighlight>
{{output}}
<pre>
(5^3)^2 = 15625
5^(3^2) = 1953125
 
fn pow( fn pow(5,3), 2 ) = 15625
fn pow( 5, fn pow(3,2 ) ) = 1953125
</pre>
 
=={{header|Go}}==
<syntaxhighlight lang="go">package main
 
import "fmt"
import "math"
 
func main() {
var a, b, c float64
a = math.Pow(5, math.Pow(3, 2))
b = math.Pow(math.Pow(5, 3), 2)
c = math.Pow(5, math.Pow(3, 2))
fmt.Printf("5^3^2 = %.0f\n", a)
fmt.Printf("(5^3)^2 = %.0f\n", b)
fmt.Printf("5^(3^2) = %.0f\n", c)
}</syntaxhighlight>
 
{{out}}
<pre>
5^3^2 = 1953125
(5^3)^2 = 15625
5^(3^2) = 1953125
</pre>
 
=={{header|Groovy}}==
 
Solution:
<syntaxhighlight lang="groovy">println(" 5 ** 3 ** 2 == " + 5**3**2)
println("(5 ** 3)** 2 == " + (5**3)**2)
println(" 5 **(3 ** 2)== " + 5**(3**2))</syntaxhighlight>
 
Output:
<pre> 5 ** 3 ** 2 == 15625
(5 ** 3)** 2 == 15625
5 **(3 ** 2)== 1953125</pre>
 
=={{header|Haskell}}==
Line 222 ⟶ 754:
J uses the same evaluation order for exponentiation as it does for assignment. That is to say: the bottom up view is right-to-left and the top-down view is left-to-right.
 
<langsyntaxhighlight Jlang="j"> 5^3^2
1.95312e6
(5^3)^2
15625
5^(3^2)
1.95312e6</langsyntaxhighlight>
 
----
Line 233 ⟶ 765:
=={{header|Java}}==
Java has no exponentiation operator, but uses the static method java.lang.Math.pow(double a, double b). There are no associativity issues.
 
=={{header|jq}}==
Requires: jq 1.5 or higher
 
jq's built-in for exponentiation is an arity-two function and thus no ambiguity arising from infix-notation is possible. Here's an example:
 
<syntaxhighlight lang="jq">jq -n 'pow(pow(5;3);2)'
15625</syntaxhighlight>
 
For chaining, one could use `reduce`:
 
<syntaxhighlight lang="jq"> def pow: reduce .[1:] as $i (.[0]; pow(.;$i))
 
[5,3,2] | pow</syntaxhighlight>
 
Result: 15625
 
=={{header|Julia}}==
{{works with|Julia|0.6}}
 
<syntaxhighlight lang="julia">@show 5 ^ 3 ^ 2 # default: power operator is read right-to-left
@show (5 ^ 3) ^ 2
@show 5 ^ (3 ^ 2)
@show reduce(^, [5, 3, 2])
@show foldl(^, [5, 3, 2]) # guarantees left associativity
@show foldr(^, [5, 3, 2]) # guarantees right associativity</syntaxhighlight>
 
{{out}}
<pre>5 ^ (3 ^ 2) = 1953125
(5 ^ 3) ^ 2 = 15625
5 ^ (3 ^ 2) = 1953125
reduce(^, [5, 3, 2]) = 15625
foldl(^, [5, 3, 2]) = 15625
foldr(^, [5, 3, 2]) = 1953125</pre>
 
=={{header|Kotlin}}==
Kotlin does not have a dedicated exponentiation operator and we would normally use Java's Math.pow function instead. However, it's possible to define an infix function which would look like an operator and here we do so for integer base and exponent. For simplicity we disallow negative exponents altogether and consider 0 ** 0 == 1. Associativity would, of course, be the same as for a normal function call.
<langsyntaxhighlight lang="scala">// version 1.0.5-2
 
infix fun Int.ipow(exp: Int): Int = when {
Line 258 ⟶ 824:
println("(5**3)**2 = ${(5 ipow 3) ipow 2}")
println("5**(3**2) = ${5 ipow (3 ipow 2)}")
}</langsyntaxhighlight>
 
{{out}}
Line 266 ⟶ 832:
5**(3**2) = 1953125
</pre>
 
=={{header|Lambdatalk}}==
 
Because lambdatalk uses prefix notation and {pow a b} accepts only two arguments, it doesn't have an expression for 5**3**2. Just showing expressions for the latter two.
 
<syntaxhighlight lang="scheme">
'{pow {pow 5 3} 2}
-> {pow {pow 5 3} 2}
'{pow 5 {pow 3 2}}
-> {pow 5 {pow 3 2}}
</syntaxhighlight>
 
=={{header|langur}}==
<syntaxhighlight lang="langur">writeln " 5^3^2: ", 5^3^2
writeln "(5^3)^2: ", (5^3)^2
writeln "5^(3^2): ", 5^(3^2)
</syntaxhighlight>
 
{{out}}
<pre> 5^3^2: 1953125
(5^3)^2: 15625
5^(3^2): 1953125
</pre>
 
=={{header|Latitude}}==
<syntaxhighlight lang="latitude">5 ^ 3 ^ 2. ;; 1953125
(5 ^ 3) ^ 2. ;; 15625
5 ^ (3 ^ 2). ;; 1953125</syntaxhighlight>
 
=={{header|Lua}}==
<langsyntaxhighlight Lualang="lua">print("5^3^2 = " .. 5^3^2)
print("(5^3)^2 = " .. (5^3)^2)
print("5^(3^2) = " .. 5^(3^2))</langsyntaxhighlight>
{{out}}
<pre>5^3^2 = 1953125
Line 276 ⟶ 870:
5^(3^2) = 1953125</pre>
Lua also has math.pow(a, b), which is identical to pow(a, b) in C. Since function arguments are contained in brackets anyway, the associativity of nested uses of math.pow will be obvious.
 
=={{header|Maple}}==
<syntaxhighlight lang="maple">5^3^2;
(5^3)^2;
5^(3^2);</syntaxhighlight>
{{Out|Output}}
<pre>Error, ambiguous use of `^`, please use parentheses
15625
1953125</pre>
 
=={{header|Mathematica}} / {{header|Wolfram Language}}==
<langsyntaxhighlight Mathematicalang="mathematica">a = "5^3^2";
Print[a <> " = " <> ToString[ToExpression[a]]]
b = "(5^3)^2";
Print[b <> " = " <> ToString[ToExpression[b]]]
c = "5^(3^2)";
Print[c <> " = " <> ToString[ToExpression[c]]]</langsyntaxhighlight>
{{out}}
<pre>5^3^2 = 1953125
(5^3)^2 = 15625
5^(3^2) = 1953125</pre>
 
=={{header|min}}==
As with other postfix languages, there is no ambiguity because all operators have the same precedence.
{{works with|min|0.19.6}}
<syntaxhighlight lang="min">5 3 2 pow pow
"5 3 2 ^ ^ " print! puts!
 
5 3 pow 2 pow
"5 3 ^ 2 ^ " print! puts!</syntaxhighlight>
{{out}}
<pre>
5 3 2 ^ ^ 1953125.0
5 3 ^ 2 ^ 15625.0
</pre>
 
=={{header|MiniScript}}==
REPL output.
{{out}}
<pre>
]5^3^2
15625
](5^3)^2
15625
]5^(3^2)
1953125
</pre>
 
=={{header|Nanoquery}}==
Nanoquery uses the '^' operator, which performs exponentiation in order like multiplication. Parenthesis are often needed to perform operations like 5^3^2 correctly.
<syntaxhighlight lang="nanoquery">% println 5^3^2
15625
% println (5^3)^2
15625
% println 5^(3^2)
1953125</syntaxhighlight>
 
=={{header|Nim}}==
<syntaxhighlight lang="nim">import math, sequtils
 
echo "5^3^2 = ", 5^3^2
echo "(5^3)^2 = ", (5^3)^2
echo "5^(3^2) = ", 5^(3^2)
echo "foldl([5, 3, 2], a^b) = ", foldl([5, 3, 2], a^b)
echo "foldr([5, 3, 2], a^b) = ", foldr([5, 3, 2], a^b)</syntaxhighlight>
 
{{out}}
<pre>5^3^2 = 1953125
(5^3)^2 = 15625
5^(3^2) = 1953125
foldl([5, 3, 2], a^b) = 15625
foldr([5, 3, 2], a^b) = 1953125</pre>
 
=={{header|OCaml}}==
OCaml language has '**' as an exponentiation symbol for floating point integers
<syntaxhighlight lang="ocaml">
# 5. ** 3. ** 2. ;;
# 5. **( 3. ** 2.) ;;
#(5. ** 3. ) **2. ;;
</syntaxhighlight>
{{out}}
<pre>
- : float = 1953125.
- : float = 1953125.
- : float = 15625.
 
</pre>
 
=={{header|PARI/GP}}==
Exponentiation is right-associative in GP.
<langsyntaxhighlight lang="parigp">f(s)=print(s" = "eval(s));
apply(f, ["5^3^2", "(5^3)^2", "5^(3^2)"]);</langsyntaxhighlight>
{{out}}
<pre>5^3^2 = 1953125
Line 299 ⟶ 968:
 
=={{header|Perl}}==
<langsyntaxhighlight lang="perl">say "$_ = " . eval($_) for qw/5**3**2 (5**3)**2 5**(3**2)/;</langsyntaxhighlight>
{{out}}
<pre>
Line 307 ⟶ 976:
</pre>
 
=={{header|Perl 6Phix}}==
{{libheader|Phix/basics}}
 
Phix has a power function rather than an infix power operator, hence there is no possible confusion.
{{Works with|rakudo|2016.08}}
<!--<syntaxhighlight lang="phix">-->
<lang perl6>use MONKEY-SEE-NO-EVAL;
<span style="color: #0000FF;">?<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #000000;">5<span style="color: #0000FF;">,<span style="color: #000000;">3<span style="color: #0000FF;">)<span style="color: #0000FF;">,<span style="color: #000000;">2<span style="color: #0000FF;">)</span>
sub demo($x) { say " $x\t───► ", EVAL $x }
<span style="color: #0000FF;">?<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #000000;">5<span style="color: #0000FF;">,<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #000000;">3<span style="color: #0000FF;">,<span style="color: #000000;">2<span style="color: #0000FF;">)<span style="color: #0000FF;">)
 
<!--</syntaxhighlight>-->
demo '5**3**2'; # show ** is right associative
demo '(5**3)**2';
demo '5**(3**2)';
 
demo '[**] 5,3,2'; # reduction form, show only final result
demo '[\**] 5,3,2'; # triangle reduction, show growing results</lang>
 
{{out}}
<pre>
15625
5**3**2 ───► 1953125
1953125
(5**3)**2 ───► 15625
5**(3**2) ───► 1953125
[**] 5,3,2 ───► 1953125
[\**] 5,3,2 ───► 2 9 1953125
</pre>
 
Note that the reduction forms automatically go right-to-left because the base operator is right-associative. Most other operators are left-associative and would automatically reduce left-to-right instead.
 
=={{header|Picat}}==
Unicode postfix exponents are supported as well:
<syntaxhighlight lang="picat">main =>
<lang perl6>demo '(5³)²';
X = 5**3**2, Y = (5**3)**2, Z = 5**(3**2),
demo '5³²';</lang>
print("5**3**2 = "), println(X),
print("(5**3)**2 = "), println(Y),
print("5**(3**2) = "), print(Z).
</syntaxhighlight>
 
{{out}}
<pre>
5**3**2 = 1953125
(5³)² ───► 15625
(5**3)**2 = 15625
5³² ───► 23283064365386962890625
5**(3**2) = 1953125
</pre>
 
The form without parentheses ends up raising to the 32nd power. Nor are you even allowed to parenthesize it the other way: <tt>5(³²)</tt> would be a syntax error. Despite all that, for programs that do a lot of squaring or cubing, the postfix forms can enhance both readability and concision.
 
=={{header|PicoLisp}}==
The PicoLisp '**' exponentiation function takes 2 arguments
<langsyntaxhighlight PicoLisplang="picolisp">: (** (** 5 3) 2)
-> 15625
 
: (** 5 (** 3 2))
-> 1953125</langsyntaxhighlight>
 
=={{header|PL/I}}==
<syntaxhighlight lang="pli">exponentiation: procedure options(main);
put skip edit('5**3**2 = ', 5**3**2) (A,F(7));
put skip edit('(5**3)**2 = ', (5**3)**2) (A,F(7));
put skip edit('5**(3**2) = ', 5**(3**2)) (A,F(7));
end exponentiation;</syntaxhighlight>
{{out}}
<pre>5**3**2 = 15625
(5**3)**2 = 15625
5**(3**2) = 1953125</pre>
 
=={{header|Python}}==
<langsyntaxhighlight lang="python">>>> 5**3**2
1953125
>>> (5**3)**2
Line 364 ⟶ 1,037:
>>> reduce(pow, (5, 3, 2))
15625
>>> </langsyntaxhighlight>
 
=={{header|Quackery}}==
Quackery uses Reverse Polish Notation, so there is no ambiguity and no need for parenthesising.
 
As a dialogue in the Quackery Shell…
 
<pre>Welcome to Quackery.
 
Enter "leave" to leave the shell.
 
/O> $ "5 3 2 ** **" dup echo$ say " returns " quackery echo cr
... $ "5 3 ** 2 **" dup echo$ say " returns " quackery echo cr
...
5 3 2 ** ** returns 1953125
5 3 ** 2 ** returns 15625
 
Stack empty.</pre>
 
=={{header|R}}==
The 'Operator Syntax and Precedence' documentation tells us that "^" is "exponentiation (right to left)". The 'Arithmetic Operators' documentation also tells us that the parser translates "**" to "^", but its depreciation status is complicated.
 
It turns out that the parser is so blind to "**" that we cannot even quote it. The following are identical:
<syntaxhighlight lang="rsplus">print(quote(5**3))
print(quote(5^3))</syntaxhighlight>
 
Another method is to use "^" as if it is an ordinary function of two arguments. It appears that "**" does not support this. As there is no potential for ambiguity in the operator precedence, we will not print this result below. For example:
<syntaxhighlight lang="rsplus">'^'('^'(5, 3), 2)</syntaxhighlight>
is clearly (5^3)^2 i.e. 15625, whereas
<syntaxhighlight lang="rsplus">'^'(5, '^'(3, 2))</syntaxhighlight>
is clearly 5^(3^2) i.e. 1953125.
 
As for actually solving the task, the requirement that each output be on a new line causes us a surprising amount of difficulty. To avoid repeating ourselves, we must almost resort to metaprogramming:
<syntaxhighlight lang="rsplus">inputs <- alist(5^3^2, (5^3)^2, 5^(3^2), 5**3**2, (5**3)**2, 5**(3**2))
invisible(sapply(inputs, function(x) cat(deparse(x), "returns: ", eval(x), "\n")))</syntaxhighlight>
 
Alternatively, we could print out a matrix or data frame:
<syntaxhighlight lang="rsplus">print(matrix(sapply(inputs, eval), dimnames = list(inputs, "Outputs")))
print(data.frame(Inputs = sapply(inputs, deparse), Outputs = sapply(inputs, eval))))</syntaxhighlight>
{{out}}
<pre>> print(quote(5**3))
5^3
> print(quote(5^3))
5^3
> invisible(sapply(inputs, function(x) cat(deparse(x), "returns: ", eval(x), "\n")))
5^3^2 returns: 1953125
(5^3)^2 returns: 15625
5^(3^2) returns: 1953125
5^3^2 returns: 1953125
(5^3)^2 returns: 15625
5^(3^2) returns: 1953125
> print(matrix(sapply(inputs, eval), dimnames = list(inputs, "Outputs")))
Outputs
5^3^2 1953125
(5^3)^2 15625
5^(3^2) 1953125
5^3^2 1953125
(5^3)^2 15625
5^(3^2) 1953125
> print(data.frame(Inputs = sapply(inputs, deparse), Outputs = sapply(inputs, eval)))
Inputs Outputs
1 5^3^2 1953125
2 (5^3)^2 15625
3 5^(3^2) 1953125
4 5^3^2 1953125
5 (5^3)^2 15625
6 5^(3^2) 1953125</pre>
 
=={{header|Racket}}==
<langsyntaxhighlight lang="racket">#lang racket
;; 5**3**2 depends on associativity of ** : Racket's (scheme's) prefix function
;; calling syntax only allows for pairs of arguments for expt.
Line 388 ⟶ 1,127:
(require (only-in srfi/1 reduce reduce-right))
(reduce expt 1 '(5 3 2))
(reduce-right expt 1 '(5 3 2))</langsyntaxhighlight>
{{out}}
<pre>prefix
Line 399 ⟶ 1,138:
14134776518227074636666380005943348126619871175004951664972849610340958208
1953125</pre>
 
=={{header|Raku}}==
(formerly Perl 6)
{{Works with|rakudo|2016.08}}
 
Note that the reduction forms automatically go right-to-left because the base operator is right-associative. Most other operators are left-associative and would automatically reduce left-to-right instead.
 
<syntaxhighlight lang="raku" line>use MONKEY-SEE-NO-EVAL;
sub demo($x) { say " $x\t───► ", EVAL $x }
 
demo '5**3**2'; # show ** is right associative
demo '(5**3)**2';
demo '5**(3**2)';
 
demo '[**] 5,3,2'; # reduction form, show only final result
demo '[\**] 5,3,2'; # triangle reduction, show growing results
 
# Unicode postfix exponents are supported as well:
 
demo '(5³)²';
demo '5³²';
</syntaxhighlight>
 
{{out}}
<pre>
5**3**2 ───► 1953125
(5**3)**2 ───► 15625
5**(3**2) ───► 1953125
[**] 5,3,2 ───► 1953125
[\**] 5,3,2 ───► 2 9 1953125
(5³)² ───► 15625
5³² ───► 23283064365386962890625
</pre>
 
The Unicode exponent form without parentheses ends up raising to the 32nd power. Nor are you even allowed to parenthesize it the other way: <tt>5(³²)</tt> would be a syntax error. Despite all that, for programs that do a lot of squaring or cubing, the postfix forms can enhance both readability and concision.
 
=={{header|Red}}==
In Red, operators simply evaluate left to right. As this differs from mathematical order of operations, Red provides the <code>math</code> function which evaluates a block using math rules instead of Red's default evaluation. One could also use the <code>power</code> function, sidestepping the issue of evaluation order entirely. All three approaches are shown.
<syntaxhighlight lang="rebol">Red["Exponentiation order"]
 
exprs: [
[5 ** 3 ** 2]
[(5 ** 3) ** 2]
[5 ** (3 ** 2)]
[power power 5 3 2] ;-- functions too
[power 5 power 3 2]
]
 
foreach expr exprs [
print [mold/only expr "=" do expr]
if find expr '** [
print [mold/only expr "=" math expr "using math"]
]
]</syntaxhighlight>
{{out}}
<pre>
5 ** 3 ** 2 = 15625
5 ** 3 ** 2 = 1953125 using math
(5 ** 3) ** 2 = 15625
(5 ** 3) ** 2 = 15625 using math
5 ** (3 ** 2) = 1953125
5 ** (3 ** 2) = 1953125 using math
power power 5 3 2 = 15625
power 5 power 3 2 = 1953125
</pre>
 
=={{header|REXX}}==
<langsyntaxhighlight lang="rexx">/*REXX program demonstrates various ways of multiple exponentiations. */
/*┌────────────────────────────────────────────────────────────────────┐
│ The REXX language uses ** for exponentionexponentiation.
│ Also, * * can be used. │
| and even */*power of*/* |
└────────────────────────────────────────────────────────────────────┘*/
 
Line 410 ⟶ 1,215:
say ' (5**3)**2 ───► ' (5**3)**2
say ' 5**(3**2) ───► ' 5**(3**2)
/*stick a fork in it, we're done.*/</langsyntaxhighlight>
'''output'''
<pre>
Line 416 ⟶ 1,221:
(5**3)**2 ───► 15625
5**(3**2) ───► 1953125
</pre>
 
=={{header|Ring}}==
 
In the Ring it is impossible to show the result of: 5^3^2
 
<syntaxhighlight lang="ring">
see "(5^3)^2 =>" + pow(pow(5,3),2) + nl
see "5^(3^2) =>" + pow(5,pow(3,2)) + nl
</syntaxhighlight>
Output:
<pre>
(5^3)^2 =>15625
5^(3^2) =>1953125
</pre>
 
=={{header|RPL}}==
When using reverse Polish notation, there is no parenthesis: the user must decide the exponentiation order.
When using algebraic notation:
'5^3^2' →NUM
'(5^3)^2' →NUM
'5^(3^2)' →NUM
{{out}}
<pre>
3: 15625
2: 15625
1: 1953125
</pre>
 
=={{header|Ruby}}==
<langsyntaxhighlight lang="ruby">ar = ["5**3**2", "(5**3)**2", "5**(3**2)", "[5,3,2].inject(:**)"]
ar.each{|exp| puts "#{exp}:\t#{eval exp}"}
</syntaxhighlight>
</lang>
{{out}}
<pre>
Line 428 ⟶ 1,260:
5**(3**2): 1953125
[5,3,2].inject(:**): 15625
</pre>
 
=={{header|Rust}}==
 
<syntaxhighlight lang="rust">fn main() {
println!("5**3**2 = {:7}", 5u32.pow(3).pow(2));
println!("(5**3)**2 = {:7}", (5u32.pow(3)).pow(2));
println!("5**(3**2) = {:7}", 5u32.pow(3u32.pow(2)));
}</syntaxhighlight>
{{out}}
<pre>
5**3**2 = 15625
(5**3)**2 = 15625
5**(3**2) = 1953125
</pre>
 
=={{header|S-BASIC}}==
The exponentiation operator ^ works on both integer and real operands. Numeric constants in expressions are taken to be of type real, which is useful here, because the third result exceeds S-BASIC's manximum integer value of 32767.
<syntaxhighlight lang = "BASIC">
print "5^3^2 : "; 5 ^ 3 ^ 2
print "(5^3)^2 : "; (5 ^ 3) ^ 2
print "5^(3^2) : "; 5 ^ (3 ^ 2)
 
end
</syntaxhighlight>
{{out}}
<pre>
5^3^2 : 15625
(5^3)^2 : 15625
5^(3^2) : 1.95312E+6
</pre>
 
=={{header|Scala}}==
Scal has no exponentiation operator, but uses the function (scala.)math.pow(x: Double, y: Double): Double function in the Scala runtime library.<br>Integer exponentiation can be done with e.g. BigInt or BigInteger.pow(n: Int) method.<br>There are no associativity issues.
 
=={{header|Seed7}}==
<syntaxhighlight lang="seed7">$ include "seed7_05.s7i";
 
const proc: main is func
begin
writeln("5**3**2 = " <& 5**3**2);
writeln("(5**3)**2 = " <& (5**3)**2);
writeln("5**(3**2) = " <& 5**(3**2));
end func;</syntaxhighlight>
 
{{out}}
<pre>
5**3**2 = 1953125
(5**3)**2 = 15625
5**(3**2) = 1953125
</pre>
 
=={{header|Sidef}}==
In Sidef, the whitespace between the operands and the operator controls the precedence of the operation.
<langsyntaxhighlight lang="ruby">var a = [
'5**3**2',
'(5**3)**2',
Line 444 ⟶ 1,326:
a.each {|e|
"%-12s == %s\n".printf(e, eval(e))
}</langsyntaxhighlight>
{{out}}
<pre>
Line 455 ⟶ 1,337:
[5,3,2]«**» == 15625
</pre>
 
=={{header|Simula}}==
<syntaxhighlight lang="simula">OutText("5** 3 **2: "); OutInt(5** 3 **2, 0); Outimage;
OutText("(5**3)**2: "); OutInt((5**3)**2, 0); Outimage;
OutText("5**(3**2): "); OutInt(5**(3**2), 0); Outimage</syntaxhighlight>
{{out}}
<pre>5** 3 **2: 15625
(5**3)**2: 15625
5**(3**2): 1953125</pre>
 
=={{header|Smalltalk}}==
Works in Smalltalk/X &sup1;
<p>Smalltalk strictly evaluates left to right; operators are not known to the language/parser, but instead message sends to the receiver on the left side (aka: virtual function calls) .
<syntaxhighlight lang="smalltalk">Transcript show:'5**3**2 => '; showCR: 5**3**2.
Transcript show:'(5**3)**2 => '; showCR: (5**3)**2.
Transcript show:'5**(3**2) => '; showCR: 5**(3**2).</syntaxhighlight>
{{out}}
<pre>
5**(3**2) => 1953125
5**3**2 => 15625
(5**3)**2 => 15625
</pre>
Note &sup1; other Smalltalk's may define ** to simply call "raisedTo:", which is standard.
 
=={{header|Stata}}==
 
<syntaxhighlight lang="stata">. di (5^3^2)
15625
 
. di ((5^3)^2)
15625
 
. di (5^(3^2))
1953125</syntaxhighlight>
 
Likewise in Mata:
 
<syntaxhighlight lang="stata">. mata (5^3^2)
15625
 
. mata ((5^3)^2)
15625
 
. mata (5^(3^2))
1953125</syntaxhighlight>
 
 
=={{header|Swift}}==
 
Swift doesn't have an exponentiation operator, however it's possible to define one, including the precedence and associativity.
 
<syntaxhighlight lang="swift">precedencegroup ExponentiationPrecedence {
associativity: left
higherThan: MultiplicationPrecedence
}
 
infix operator ** : ExponentiationPrecedence
 
@inlinable
public func ** <T: BinaryInteger>(lhs: T, rhs: T) -> T {
guard lhs != 0 else {
return 1
}
 
var x = lhs
var n = rhs
var y = T(1)
 
while n > 1 {
switch n & 1 {
case 0:
n /= 2
case 1:
y *= x
n = (n - 1) / 2
case _:
fatalError()
}
 
x *= x
}
 
return x * y
}
 
print(5 ** 3 ** 2)
print((5 ** 3) ** 2)
print(5 ** (3 ** 2))</syntaxhighlight>
 
{{out}}
 
<pre>15625
15625
1953125</pre>
 
=={{header|Tcl}}==
<langsyntaxhighlight lang="tcl">foreach expression {5**3**2 (5**3)**2 5**(3**2)} {
puts "${expression}:\t[expr $expression]"
}</langsyntaxhighlight>
{{out}}
<pre>
Line 467 ⟶ 1,443:
</pre>
There's also a binary <code>pow()</code> expression function that always converts its arguments to floating point numbers and then applies the exponentiation operation; it's now largely obsolete because of the <code>**</code> operator, but is retained for backward compatibility with older programs.
 
=={{header|VBA}}==
<syntaxhighlight lang="vb">Public Sub exp()
Debug.Print "5^3^2", 5 ^ 3 ^ 2
Debug.Print "(5^3)^2", (5 ^ 3) ^ 2
Debug.Print "5^(3^2)", 5 ^ (3 ^ 2)
End Sub</syntaxhighlight>{{out}}
<pre>5^3^2 15625
(5^3)^2 15625
5^(3^2) 1953125
</pre>
 
=={{header|VBScript}}==
<syntaxhighlight lang="vb">
<lang vb>
WScript.StdOut.WriteLine "5^3^2 => " & 5^3^2
WScript.StdOut.WriteLine "(5^3)^2 => " & (5^3)^2
WScript.StdOut.WriteLine "5^(3^2) => " & 5^(3^2)
</syntaxhighlight>
</lang>
 
{{Out}}
Line 480 ⟶ 1,467:
(5^3)^2 => 15625
5^(3^2) => 1953125
</pre>
 
=={{header|Verbexx}}==
<syntaxhighlight lang="verbexx">// Exponentiation order example:
 
@SAY "5**3**2 = " ( 5**3**2 );
@SAY "(5**3)**2 = " ( (5**3)**2 );
@SAY "5**(3**2) = " ( 5**(3**2) );
 
/] Output:
5**3**2 = 1953125
(5**3)**2 = 15625
5**(3**2) = 1953125</syntaxhighlight>
 
=={{header|Wren}}==
{{libheader|Wren-fmt}}
Wren doesn't have an exponentiation operator as such but the Num class has a ''pow'' method which does the same thing.
<syntaxhighlight lang="wren">import "./fmt" for Fmt
 
var ops = [ "5**3**2", "(5**3)**2", "5**(3**2)" ]
var results = [ 5.pow(3).pow(2), (5.pow(3)).pow(2), 5.pow(3.pow(2)) ]
for (i in 0...ops.count) {
Fmt.print("$-9s -> $d", ops[i], results[i])
}</syntaxhighlight>
 
{{out}}
<pre>
5**3**2 -> 15625
(5**3)**2 -> 15625
5**(3**2) -> 1953125
</pre>
 
=={{header|XPL0}}==
XPL0 doesn't have an exponentiation operator, but it does have a Pow intrinsic (in the 32-bit versions).
<syntaxhighlight lang "XPL0">[Format(1, 0);
Text(0, "5**3**2 = "); RlOut(0, Pow(5., Pow(3., 2.))); CrLf(0); \right associative
Text(0, "(5**3)**2 = "); RlOut(0, Pow(Pow(5., 3.), 2.)); CrLf(0);
Text(0, "5**(3**2) = "); RlOut(0, Pow(5., Pow(3., 2.))); CrLf(0);
]</syntaxhighlight>
{{out}}
<pre>
5**3**2 = 1953125
(5**3)**2 = 15625
5**(3**2) = 1953125
</pre>
 
Line 485 ⟶ 1,517:
{{trans|C}}
zkl does not have an exponentiation operator but floats have a pow method.
<langsyntaxhighlight lang="zkl">println("5 ^ 3 ^ 2 = %,d".fmt((5.0).pow((3.0).pow(2))));
println("(5 ^ 3) ^ 2 = %,d".fmt((5.0).pow(3).pow(2)));
println("5 ^ (3 ^ 2) = %,d".fmt((5.0).pow((3.0).pow(2))));</langsyntaxhighlight>
{{out}}
<pre>
9,485

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