Eban numbers: Difference between revisions
→{{header|ALGOL 68}}: Removed unnecessary test
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:* The MathWorld entry: [http://mathworld.wolfram.com/EbanNumber.html eban numbers].
:* The OEIS entry: [http://oeis.org/A006933 A6933, eban numbers].
:* [[Number names]].
<br><br>
Line 81 ⟶ 82:
Number of eban numbers up to and including 10000000: 1599
</pre>
=={{header|ALGOL 68}}==
{{Trans|Lua|for the eban number enumerating code}}
{{Trans|Phix|for the eban number counting code}}
<syntaxhighlight lang="algol68">
BEGIN # Eban numbers - translated from the Lua and Phix samples #
MODE INTERVAL = STRUCT( INT start, end, BOOL print );
[]INTERVAL intervals = ( ( 2, 1000, TRUE )
, ( 1000, 4000, TRUE )
, ( 2, 10000, FALSE )
, ( 2, 1000000, FALSE )
, ( 2, 10000000, FALSE )
, ( 2, 100000000, FALSE )
, ( 2, 1000000000, FALSE )
);
FOR intp FROM LWB intervals TO UPB intervals DO
INTERVAL intv = intervals[ intp ];
IF start OF intv = 2 THEN
print( ( "eban numbers up to and including ", whole( end OF intv, 0 ), ":" ) )
ELSE
print( ( "eban numbers between ", whole( start OF intv, 0 )
, " and ", whole( end OF intv, 0 ), " (inclusive)"
)
)
FI;
print( ( newline ) );
IF NOT print OF intv THEN
# calculate the count, as in the Phix sample #
# end OF intv must be a power of 10 #
INT p10 := 0;
INT v := end OF intv;
WHILE v > p10 DO
p10 +:= 1;
v OVERAB 10
OD;
INT n = p10 - ( p10 OVER 3 );
INT p5 = n OVER 2;
INT p4 = ( n + 1 ) OVER 2;
print( ( "count = ", whole( ( ( 5 ^ p5 ) * ( 4 ^ p4 ) ) - 1, 0 ), newline ) )
ELSE
# enumerate the eban numbers, as in the Lua and other samples #
INT count := 0;
FOR i FROM start OF intv BY 2 TO end OF intv DO
INT b = i OVER 1 000 000 000;
INT r := i MOD 1 000 000 000;
INT m := r OVER 1 000 000;
r := i MOD 1 000 000;
INT t := r OVER 1 000;
r := r MOD 1 000;
IF m >= 30 AND m <= 66 THEN m MODAB 10 FI;
IF t >= 30 AND t <= 66 THEN t MODAB 10 FI;
IF r >= 30 AND r <= 66 THEN r MODAB 10 FI;
IF b = 0 OR b = 2 OR b = 4 OR b = 6 THEN
IF m = 0 OR m = 2 OR m = 4 OR m = 6 THEN
IF t = 0 OR t = 2 OR t = 4 OR t = 6 THEN
IF r = 0 OR r = 2 OR r = 4 OR r = 6 THEN
print( ( whole( i, 0 ), " " ) );
count +:= 1
FI
FI
FI
FI
OD;
print( ( newline, "count = ", whole( count, 0 ), newline ) )
FI;
print( ( newline ) )
OD
END
</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive)
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999
</pre>
Line 767 ⟶ 865:
eban numbers up to an including 1000000000:
count = 7999</pre>
=={{header|EasyLang}}==
{{trans|AWK}}
<syntaxhighlight lang=easylang>
func x n .
if n = 0 or n = 2 or n = 4 or n = 6
return 1
.
.
proc go start stop printable . .
write start & " - " & stop & ":"
for i = start step 2 to stop
b = i div 1000000000
r = i mod 1000000000
m = r div 1000000
r = i mod 1000000
t = r div 1000
r = r mod 1000
if m >= 30 and m <= 66
m = m mod 10
.
if t >= 30 and t <= 66
t = t mod 10
.
if r >= 30 and r <= 66
r = r mod 10
.
if x b = 1 and x m = 1 and x t = 1 and x r = 1
count += 1
if printable = 1
write " " & i
.
.
.
print " (count=" & count & ")"
.
go 2 1000 1
go 1000 4000 1
go 2 10000 0
go 2 100000 0
go 2 1000000 0
go 2 10000000 0
go 2 100000000 0
</syntaxhighlight>
=={{header|Factor}}==
Line 888 ⟶ 1,030:
=={{header|Fōrmulæ}}==
{{FormulaeEntry|page=https://formulae.org/?script=examples/Eban_numbers}}
=={{header|Go}}==
Line 1,132 ⟶ 1,270:
1e7 1599
</syntaxhighlight>
Alternatively we could construct a sequence of eban numbers sufficient to satisfy some limit and then filter out any which exceed our limit:
<syntaxhighlight lang=J>ebanseq=: {{ (#~ y>:])}.,@([+/~1000*])^:(6<.<.1000^.y)~(,0 2 4 6+/~10*0 3 4 5 6) }}
(,:&":~ #) ebanseq 1000
19
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
(,:&":~ #) (#~ 1000<])ebanseq 4000
21
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
# ebanseq 1e4
79
# ebanseq 1e5
399
# ebanseq 1e6
399
# ebanseq 1e7
1599
# ebanseq 1e8
7999
# ebanseq 1e9
7999
# ebanseq 1e10
31999
# ebanseq 1e11
159999
# ebanseq 1e12
159999
# ebanseq 1e13
639999
# ebanseq 1e14
3199999
# ebanseq 1e15
3199999
# ebanseq 1e16
12799999
# ebanseq 1e17
63999999</syntaxhighlight>
=={{header|Java}}==
Line 1,362 ⟶ 1,539:
eban numbers up to and including 100000000: 7999
eban numbers up to and including 1000000000: 7999</pre>
=={{header|K}}==
{{works with|ngn/k}}
<syntaxhighlight lang=K>eban: {1_((x<)_,/(,/(2*!4)+/:10*0,3+!4)+/:1000*)/0}@_:
#eban 1000
19
#(1000>)_eban 4000
21
#eban 1e4
79
#eban 1e5
399
#eban 1e6
399
#eban 1e7
1599
#eban 1e8
7999
#eban 1e9
7999
#eban 1e10
31999
#eban 1e11
159999
#eban 1e12
159999
#eban 1e13
639999
#eban 1e14
3199999</syntaxhighlight>
=={{header|Kotlin}}==
Line 1,618 ⟶ 1,826:
Number of eban numbers up to and including 10000000: 1599
</pre>
===Algorithmic computation===
{{trans|Phix}}
Line 1,693 ⟶ 1,900:
Time: 189 microseconds and 491 nanoseconds</pre>
=={{header|Odin}}==
<syntaxhighlight lang="Go">
package eban_numbers
/* imports */
import "core:fmt"
/* globals */
Range :: struct {
start: i32,
end: i32,
print: bool,
}
printcounter: i32 = 0
/* main block */
main :: proc() {
rgs := [?]Range{
{2, 1000, true},
{1000, 4000, true},
{2, 1e4, false},
{2, 1e5, false},
{2, 1e6, false},
{2, 1e7, false},
{2, 1e8, false},
{2, 1e9, false},
}
for rg in rgs {
if rg.start == 2 {
fmt.printf("eban numbers up to and including %d:\n", rg.end)
} else {
fmt.printf("eban numbers between %d and %d (inclusive):\n", rg.start, rg.end)
}
count := i32(0)
for i := rg.start; i <= i32(rg.end); i += i32(2) {
b := i / 1000000000
r := i % 1000000000
m := r / 1000000
r = i % 1000000
t := r / 1000
r %= 1000
if m >= 30 && m <= 66 {
m %= 10
}
if t >= 30 && t <= 66 {
t %= 10
}
if r >= 30 && r <= 66 {
r %= 10
}
if b == 0 || b == 2 || b == 4 || b == 6 {
if m == 0 || m == 2 || m == 4 || m == 6 {
if t == 0 || t == 2 || t == 4 || t == 6 {
if r == 0 || r == 2 || r == 4 || r == 6 {
if rg.print {
fmt.printf("%d ", i)
}
count += 1
}
}
}
}
}
if rg.print {
fmt.println()
}
fmt.println("count =", count, "\n")
}
}
</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999
</pre>
=={{header|Perl}}==
Line 2,177 ⟶ 2,480:
Run time in seconds: 1134.289519125
</pre>
=={{header|Quackery}}==
<syntaxhighlight lang="Quackery"> [ 20 /mod
4 /mod
[ table 0 2 4 6 ]
swap
[ table 0 30 40 50 60 ]
+
over 0 = iff nip done
swap recurse 1000 * + ] is n->eban ( n --> n )
[] 1
[ dup n->eban
dup 10000001 < while
swap dip join
1+ again ]
2drop
dup dup
say "eban numbers up to and including 1000:"
cr
findwith [ 1000 > ] [ ]
split drop dup echo cr
say "count: " size echo
cr cr
say "eban numbers between 1000 and 4000 (inclusive):"
cr
dup dup
findwith [ 999 > ] [ ]
split nip
dup
findwith [ 4001 > ] [ ]
split drop dup echo cr
say "count: " size echo
cr cr
say "number of eban numbers up to and including 10000: "
dup findwith [ 10001 > ] [ ]
echo
cr cr
say "number of eban numbers up to and including 100000: "
dup findwith [ 100001 > ] [ ]
echo
cr cr
say "number of eban numbers up to and including 1000000: "
dup findwith [ 1000001 > ] [ ]
echo
cr cr
say "number of eban numbers up to and including 10000000: "
findwith [ 10000001 > ] [ ]
echo</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000
[ 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 ]
count: 19
eban numbers between 1000 and 4000 (inclusive):
[ 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 ]
count: 21
number of eban numbers up to and including 10000: 79
number of eban numbers up to and including 100000: 399
number of eban numbers up to and including 1000000: 399
number of eban numbers up to and including 10000000: 1599</pre>
=={{header|Raku}}==
Line 2,432 ⟶ 2,803:
1599 eban numbers found for: 1 -10000000
═════════════════════════════════════════════════════════════════════════════════════════════════════════
</pre>
=={{header|RPL}}==
{{trans|Julia}}
{{works with|HP|49}}
« '''IF''' DUP '''THEN'''
1000000000 IDIV2
1000000 IDIV2
1000 IDIV2
3 →LIST
« → x « 30 x ≤ x 66 ≤ AND x 10 MOD x IFTE » » MAP
+
« { 0 2 4 6 } SWAP POS » MAP ΠLIST
'''END'''
» » '<span style="color:blue">EBAN?</span>' STO
« { }
UNROT '''FOR''' j
'''IF''' j <span style="color:blue">EBAN?</span> '''THEN''' j + '''END'''
'''NEXT'''
» » '<span style="color:blue">TASK1</span>' STO
« 0
1 ROT '''FOR''' j
'''IF''' j <span style="color:blue">EBAN?</span> '''THEN''' 1 + '''END'''
'''NEXT'''
» » '<span style="color:blue">TASK2</span>' STO
1 1000 <span style="color:blue">TASK1</span>
1000 4000 <span style="color:blue">TASK1</span>
10000 <span style="color:blue">TASK2</span>
{{out}}
<pre>
3: { 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 }
2: { 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 }
1: 79
</pre>
Line 2,684 ⟶ 3,091:
</pre>
=={{header|uBasic/4tH}}==
{{trans|Yabasic}}
<syntaxhighlight lang="qbasic">Push 2, 10^7, 0
Push 2, 10^6, 0
Push 2, 10^5, 0
Push 2, 10^4, 0
Push 1000, 4000, 1
Push 2, 1000, 1
z = XOR(NOT(0), 6)
Do While Used()
p = Pop() : e = Pop() : s = Pop()
If s = 2 Then
Print "eban numbers up to and including ";e
Else
Print "eban numbers between ";s;" and ";e;" (inclusive):"
EndIf
c = 0
For i = s To e Step 2
b = i / 1000000000
m = (i % 1000000000) / 1000000
r = i % 1000000
t = r / 1000
r = r % 1000
If ((m < 30) = 0) * ((m > 66) = 0) Then m = m % 10
If ((t < 30) = 0) * ((t > 66) = 0) Then t = t % 10
If ((r < 30) = 0) * ((r > 66) = 0) Then r = r % 10
If (AND(b, z) = 0) * (AND(m, z) = 0) * (AND(t, z) = 0) * (AND(r, z) = 0) Then
If p Then Print i;" "; : Fi
c = c + 1
EndIf
Next
If p Then Print
Print "count = ";c : Print
Loop</syntaxhighlight >
=={{header|Visual Basic .NET}}==
{{trans|D}}
Line 2,784 ⟶ 3,231:
count = 7999</pre>
=={{header|V (Vlang)}}==
{{trans|Go}}
<syntaxhighlight lang="v (vlang)">
struct Range {
start i64
Line 2,878 ⟶ 3,325:
=={{header|Wren}}==
{{trans|Go}}
<syntaxhighlight lang="
[2, 1000, true],
[1000, 4000, true],
Line 2,947 ⟶ 3,394:
count = 7999
eban numbers up to and including 1000000000
count = 7999
</pre>
=={{header|XPL0}}==
{{trans|Wren}}
<syntaxhighlight lang "XPL0">include xpllib; \for Print
int Rgs, Rg, Count, I, B, R, M, T;
[Rgs:= [
[2, 1000, true],
[1000, 4000, true],
[2, 10000, false],
[2, 100000, false],
[2, 1000000, false],
[2, 10000000, false],
[2, 100000000, false],
[2, 1000000000, false] ];
for Rg:= 0 to 8-1 do
[if Rgs(Rg,0) = 2 then
Print("eban numbers up to and including %d\n", Rgs(Rg,1))
else
Print("eban numbers between %d and %d (inclusive):\n", Rgs(Rg,0), Rgs(Rg,1));
Count:= 0;
I:= Rgs(Rg,0);
while I <= Rgs(Rg,1) do
[B:= (I/1_000_000_000);
M:= rem(0) / 1_000_000;
T:= rem(0) / 1_000;
R:= rem(0);
if M >= 30 and M <= 66 then M:= rem(M/10);
if T >= 30 and T <= 66 then T:= rem(T/10);
if R >= 30 and R <= 66 then R:= rem(R/10);
if B = 0 or B = 2 or B = 4 or B = 6 then
if M = 0 or M = 2 or M = 4 or M = 6 then
if T = 0 or T = 2 or T = 4 or T = 6 then
if R = 0 or R = 2 or R = 4 or R = 6 then
[if Rgs(Rg,2) then Print("%d ", I);
Count:= Count+1;
];
I:= I+2;
];
if Rgs(Rg,2) then CrLf(0);
Print("count = %d\n", Count);
];
]</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000
count = 79
eban numbers up to and including 100000
count = 399
eban numbers up to and including 1000000
count = 399
eban numbers up to and including 10000000
count = 1599
eban numbers up to and including 100000000
count = 7999
eban numbers up to and including 1000000000
count = 7999
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