Distinct power numbers: Difference between revisions

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(Ada version)
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<br>4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
<br><br>
 
=={{header|11l}}==
{{trans|Python}}
 
<syntaxhighlight lang="11l">print(sorted(Array(Set(cart_product(2..5, 2..5).map((a, b) -> a ^ b)))))</syntaxhighlight>
 
{{out}}
<pre>
[4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125]
</pre>
 
=={{header|Action!}}==
{{libheader|Action! Tool Kit}}
<langsyntaxhighlight Actionlang="action!">INCLUDE "D2:SORT.ACT" ;from the Action! Tool Kit
 
INT FUNC Power(INT a,b)
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PrintI(a(i)) Put(32)
OD
RETURN</langsyntaxhighlight>
{{out}}
[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Distinct_power_numbers.png Screenshot from Atari 8-bit computer]
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=={{header|Ada}}==
<langsyntaxhighlight Adalang="ada">with Ada.Text_Io;
with Ada.Containers.Doubly_Linked_Lists;
 
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New_Line;
 
end Power_Numbers;</langsyntaxhighlight>
{{out}}
<pre> 4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125 </pre>
 
=={{header|ALGOL 68}}==
<langsyntaxhighlight lang="algol68">BEGIN # show in order, distinct values of a^b where 2 <= a <= b <= 5 #
INT max number = 5;
INT min number = 2;
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OD;
print( ( newline ) )
END</langsyntaxhighlight>
{{out}}
<pre>
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=={{header|APL}}==
{{works with|Dyalog APL}}
<syntaxhighlight lang APL="apl">(⊂∘⍋⌷⊣)∪,∘.*⍨1+⍳4</langsyntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
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===Idiomatic===
Uses an extravagantly long list, but gets the job done quickly and easily.
<langsyntaxhighlight lang="applescript">on task()
script o
property output : {}
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end task
 
task()</langsyntaxhighlight>
 
{{output}}
<langsyntaxhighlight lang="applescript">{4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125}</langsyntaxhighlight>
----
 
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Composing a solution from generic primitives, for speed of drafting, and ease of refactoring:
 
<langsyntaxhighlight lang="applescript">use framework "Foundation"
use scripting additions
 
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((current application's NSArray's arrayWithArray:xs)'s ¬
sortedArrayUsingSelector:"compare:") as list
end sort</langsyntaxhighlight>
{{Out}}
<pre>{4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125}</pre>
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===AppleScriptObjC===
Throwing together a solution using the most appropriate methods for efficiency and legibility.
<langsyntaxhighlight lang="applescript">use AppleScript version "2.4" -- Mac OS X 10.10 (Yosemite) or later.
use framework "Foundation"
 
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end task
 
task()</langsyntaxhighlight>
 
{{output}}
<langsyntaxhighlight lang="applescript">{4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125}</langsyntaxhighlight>
 
=={{header|Arturo}}==
 
<syntaxhighlight lang="rebol">print sort unique flatten map 2..5 'a [
map 2..5 'b -> a^b
]</syntaxhighlight>
 
{{out}}
 
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|BCPL}}==
<langsyntaxhighlight lang="bcpl">get "libhdr"
 
let pow(n, p) =
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if i=0 | v!i ~= v!(i-1) do writef("%N ", v!i)
wrch('*N')
$)</langsyntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|BQN}}==
<syntaxhighlight lang ="bqn">∧⍷⥊⋆⌜˜ 2+↕4</langsyntaxhighlight>
{{out}}
<pre>⟨ 4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125 ⟩</pre>
 
=={{header|C}}==
<langsyntaxhighlight lang="c">#include <stdio.h>
#include <stdlib.h>
#include <math.h>
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printf("\n");
return 0;
}</langsyntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|C++}}==
<langsyntaxhighlight lang="cpp">#include <iostream>
#include <set>
#include <cmath>
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std::cout << std::endl;
return 0;
}</langsyntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|F_Sharp|F#}}==
<langsyntaxhighlight lang="fsharp">
set[for n in 2..5 do for g in 2..5->pown n g]|>Set.iter(printf "%d ")
</syntaxhighlight>
</lang>
{{out}}
<pre>
4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125
</pre>
 
=={{header|Delphi}}==
{{works with|Delphi|6.0}}
{{libheader|Classes,SysUtils,StdCtrls,Math}}
Uses Delphi's standard StringList control to avoid duplicates and keep the list storted. It uses a trick to make the strings sorted numerically. The number strings are stored with leading zeros to make them sort numericall and the actual number is stored as an object so it can be retrieved without the leading zeros.
 
<syntaxhighlight lang="Delphi">
 
procedure FindDistinctPowers(Memo: TMemo);
{Display list of numbers a^b sort and exclude duplicates}
{tricks Delphi TStringGrid into sorting numerically}
var A,B,I,P: integer;
var SL: TStringList;
begin
SL:=TStringList.Create;
try
SL.Duplicates:=dupIgnore;
SL.Sorted:=True;
for A:=2 to 5 do
for B:=2 to 5 do
begin
P:=Trunc(Power(A,B));
{Add leading zeros to number so it sorts numerically}
SL.AddObject(FormatFloat('00000',P),Pointer(P));
end;
Memo.Text:=IntToStr(integer(SL.Objects[0]));
for I:=1 to SL.Count-1 do Memo.Text:=Memo.Text+','+IntToStr(integer(SL.Objects[I]));
finally SL.Free; end;
end;
 
 
</syntaxhighlight>
{{out}}
<pre>
4,8,9,16,25,27,32,64,81,125,243,256,625,1024,3125
 
</pre>
 
 
=={{header|Factor}}==
{{works with|Factor|0.99 2021-06-02}}
<langsyntaxhighlight lang="factor">USING: kernel math.functions math.ranges prettyprint sequences
sets sorting ;
 
2 5 [a,b] dup [ ^ ] cartesian-map concat members natural-sort .</langsyntaxhighlight>
{{out}}
<pre>
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=={{header|FreeBASIC}}==
<langsyntaxhighlight lang="freebasic">
redim arr(-1) as uinteger
dim as uinteger i
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if arr(i)<>arr(i-1) then print arr(i),
next i
</syntaxhighlight>
</lang>
 
=={{header|Go}}==
{{trans|Wren}}
{{libheader|Go-rcu}}
<langsyntaxhighlight lang="go">package main
 
import (
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}
fmt.Println("\nFound", len(pows), "such numbers.")
}</langsyntaxhighlight>
 
{{out}}
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=={{header|Haskell}}==
<langsyntaxhighlight lang="haskell">import qualified Data.Set as S
 
 
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main =
print $
distinctPowerNumbers 2 5</langsyntaxhighlight>
{{Out}}
<pre>[4,8,9,16,25,27,32,64,81,125,243,256,625,1024,3125]</pre>
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or, as a one-off list comprehension:
 
<langsyntaxhighlight lang="haskell">import qualified Data.Set as S
 
main :: IO ()
main =
(print . S.elems . S.fromList) $
(\xs -> [x ^ y | x <- xs, y <- xs]) [2 .. 5]</langsyntaxhighlight>
 
or a liftA2 expression:
<langsyntaxhighlight lang="haskell">import Control.Applicative (liftA2)
import Control.Monad (join)
import qualified Data.Set as S
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join
(liftA2 (^))
[2 .. 5]</langsyntaxhighlight>
 
which can always be reduced (shedding imports) to the pattern:
<langsyntaxhighlight lang="haskell">import qualified Data.Set as S
 
main :: IO ()
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(print . S.elems . S.fromList) $
(\xs -> (^) <$> xs <*> xs)
[2 .. 5]</langsyntaxhighlight>
 
{{Out}}
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=={{header|J}}==
<langsyntaxhighlight lang="j">~./:~;^/~2+i.4</langsyntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
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For relatively small integers, such as involved in the specified task, the built-in function `pow/2` does the job:
<langsyntaxhighlight lang="jq">[range(2;6) as $a | range(2;6) as $b | pow($a; $b)] | unique</langsyntaxhighlight>
{{out}}
<pre>
[4,8,9,16,25,27,32,64,81,125,243,256,625,1024,3125]
</pre>
However, if using gojq, then for unbounded precision, a special-purpose "power" function is needed:<langsyntaxhighlight lang="jq">def power($b): . as $in | reduce range(0;$b) as $i (1; . * $in);
 
[range(2;6) as $a | range(2;6) as $b | $a|power($b)] | unique</langsyntaxhighlight>
{{out}}
As above.
=={{header|Julia}}==
<langsyntaxhighlight lang="julia">println(sort(unique([a^b for a in 2:5, b in 2:5])))</langsyntaxhighlight>{{out}}
<pre>[4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125]</pre>
 
=={{header|Mathematica}}/{{header|Wolfram Language}}==
<langsyntaxhighlight Mathematicalang="mathematica">Union @@ Table[a^b, {a, 2, 5}, {b, 2, 5}]</langsyntaxhighlight>
{{out}}
<pre>{4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125}</pre>
 
=={{header|Nim}}==
<langsyntaxhighlight Nimlang="nim">import algorithm, math, sequtils, strutils, sugar
 
let list = collect(newSeq):
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for b in 2..5: a^b
 
echo sorted(list).deduplicate(true).join(" ")</langsyntaxhighlight>
 
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|OCaml}}==
<syntaxhighlight lang="ocaml">module IntSet = Set.Make(Int)
 
let pow x =
let rec aux acc b = function
| 0 -> acc
| y -> aux (if y land 1 = 0 then acc else acc * b) (b * b) (y lsr 1)
in
aux 1 x
 
let distinct_powers first count =
let sq = Seq.(take count (ints first)) in
IntSet.of_seq (Seq.map_product pow sq sq)
 
let () = distinct_powers 2 4
(* output *)
|> IntSet.to_seq |> Seq.map string_of_int
|> List.of_seq |> String.concat " " |> print_endline</syntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|Phix}}==
<!--<langsyntaxhighlight Phixlang="phix">(phixonline)-->
<span style="color: #008080;">with</span> <span style="color: #008080;">javascript_semantics</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">sqpn</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">n</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sq_power</span><span style="color: #0000FF;">(</span><span style="color: #000000;">n</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">3</span><span style="color: #0000FF;">,</span><span style="color: #000000;">4</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">})</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">res</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">apply</span><span style="color: #0000FF;">(</span><span style="color: #004600;">true</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">sprintf</span><span style="color: #0000FF;">,{{</span><span style="color: #008000;">"%,5d"</span><span style="color: #0000FF;">},</span><span style="color: #7060A8;">unique</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">join</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">apply</span><span style="color: #0000FF;">({</span><span style="color: #000000;">2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">3</span><span style="color: #0000FF;">,</span><span style="color: #000000;">4</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">},</span><span style="color: #000000;">sqpn</span><span style="color: #0000FF;">),</span><span style="color: #008000;">""</span><span style="color: #0000FF;">))})</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%d found:\n%s\n"</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">res</span><span style="color: #0000FF;">),</span><span style="color: #7060A8;">join_by</span><span style="color: #0000FF;">(</span><span style="color: #000000;">res</span><span style="color: #0000FF;">,</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">,</span><span style="color: #008000;">" "</span><span style="color: #0000FF;">)})</span>
<!--</langsyntaxhighlight>-->
{{out}}
<pre>
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=={{header|Perl}}==
<langsyntaxhighlight lang="perl">#!/usr/bin/perl -l
 
use strict; # https://rosettacode.org/wiki/Distinct_power_numbers
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use List::Util qw( uniq );
 
print join ', ', sort { $a <=> $b } uniq map { my $e = $_; map $_ ** $e, 2 .. 5} 2 .. 5;</langsyntaxhighlight>
{{out}}
<pre>
Line 589 ⟶ 668:
 
=={{header|Python}}==
<langsyntaxhighlight lang="python">from itertools import product
print(sorted(set(a**b for (a,b) in product(range(2,6), range(2,6)))))</langsyntaxhighlight>
{{out}}
<pre>[4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125]</pre>
Line 596 ⟶ 675:
 
Or, for variation, generalizing a little in terms of '''starmap''' and '''pow''':
<langsyntaxhighlight lang="python">'''Distinct power numbers'''
 
from itertools import product, starmap
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# MAIN ---
if __name__ == '__main__':
main()</langsyntaxhighlight>
{{Out}}
<pre>[4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125]</pre>
Line 633 ⟶ 712:
=={{header|R}}==
This only takes one line.
<langsyntaxhighlight Rlang="rsplus">unique(sort(rep(2:5, each = 4)^rep(2:5, times = 4)))</langsyntaxhighlight>
{{out}}
<pre> [1] 4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
 
=={{header|Quackery}}==
 
<syntaxhighlight lang="Quackery"> [ [] swap
behead swap
witheach
[ 2dup = iff
drop done
dip join ]
join ] is unique ( [ --> [ )
 
[]
4 times
[ i 2 +
4 times
[ dup i 2 + **
rot join swap ]
drop ]
sort unique echo</syntaxhighlight>
 
{{out}}
 
<pre>[ 4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125 ]</pre>
 
=={{header|Raku}}==
<syntaxhighlight lang="raku" perl6line>put squish sort [X**] (2..5) xx 2;</langsyntaxhighlight>
{{out}}
<pre>4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125</pre>
Line 644 ⟶ 746:
=={{header|REXX}}==
With this version of REXX, &nbsp; there's no need to sort the found numbers, &nbsp; or to eliminate duplicates.
<langsyntaxhighlight lang="rexx">/*REXX pgm finds and displays distinct power integers: a^b, where a and b are 2≤both≤5*/
parse arg lo hi cols . /*obtain optional arguments from the CL*/
if lo=='' | lo=="," then lo= 2 /*Not specified? Then use the default.*/
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getMin: parse arg z .; p= 1; #= words($$) /*assume min; # words in $$.*/
do m=2 for #-1; a= word($$, m); if a>=z then iterate; z= a; p= m
end /*m*/; $$= delword($$, p, 1); return /*delete the smallest number.*/</langsyntaxhighlight>
{{out|output|text=&nbsp; when using the default inputs:}}
<pre>
Line 716 ⟶ 818:
 
=={{header|Ring}}==
<langsyntaxhighlight lang="ring">
load "stdlib.ring"
 
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see "Found " + row + " numbers" + nl
see "done..." + nl
</syntaxhighlight>
</lang>
{{out}}
<pre>
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Found 15 numbers
done...
</pre>
 
=={{header|RPL}}==
≪ { }
2 5 '''FOR''' a
2 5 '''FOR''' b
a b ^
'''IF''' DUP2 POS '''THEN''' DROP '''ELSE''' + '''END'''
'''NEXT NEXT''' SORT
≫ '<span style="color:blue">DPOWR</span>' STO
{{out}}
<pre>
1: { 4 8 9 16 25 27 32 64 81 125 243 256 625 1024 3125 }
</pre>
=={{header|Ruby}}==
<syntaxhighlight lang="ruby">a = (2..5).to_a
p a.product(a).map{_1 ** _2}.sort.uniq</syntaxhighlight>
{{out}}
<pre>
[4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125]
</pre>
 
=={{header|Sidef}}==
<langsyntaxhighlight lang="ruby">[2..5]*2 -> cartesian.map_2d {|a,b| a**b }.sort.uniq.say</langsyntaxhighlight>
 
Alternative solution:
<langsyntaxhighlight lang="ruby">2..5 ~X** 2..5 -> sort.uniq.say</langsyntaxhighlight>
{{out}}
<pre>
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{{libheader|Wren-seq}}
{{libheader|Wren-fmt}}
<langsyntaxhighlight ecmascriptlang="wren">import "./seq" for Lst
import "./fmt" for Fmt
 
var pows = []
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pows = Lst.distinct(pows).sort()
System.print("Ordered distinct values of a ^ b for a in [2..5] and b in [2..5]:")
for (chunk in Lst.chunks(pows, 5)) Fmt.printtprint("$,5d", chunkpows, 5)
System.print("\nFound %(pows.count) such numbers.")</langsyntaxhighlight>
 
{{out}}
Line 801 ⟶ 923:
 
=={{header|XPL0}}==
<langsyntaxhighlight XPL0lang="xpl0">int A, B, N, Last, Next;
[Last:= 0;
loop [Next:= -1>>1; \infinity
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Last:= Next;
];
]</langsyntaxhighlight>
 
{{out}}
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