Cubic special primes: Difference between revisions

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see "prime1 prime2 Gap" + nl
see "prime1 prime2 Gap Cbrt" + nl
for n = 1 to Len(Primes)-1
for n = 1 to Len(Primes)-1
diff = Primes[n+1] - Primes[n]
diff = Primes[n+1] - Primes[n]
see ""+ Primes[n] + " " + Primes[n+1] + " " + diff + nl
for m = 1 to diff
if pow(m,3) = diff
cbrt = m
exit
ok
next
see ""+ Primes[n] + " " + Primes[n+1] + " " + diff + " " + cbrt + nl
next
next

see "Found " + Len(Primes) + " of the smallest primes < 15,000 such that the difference of successive terma are the smallest cubic numbers" + nl
see "Found " + Len(Primes) + " of the smallest primes < 15,000 such that the difference of successive terma are the smallest cubic numbers" + nl

see "done..." + nl
see "done..." + nl
</lang>
</lang>
{{out}}
{{out}}
<pre>
<pre>
working...
working...
prime1 prime2 Gap
prime1 prime2 Gap Cbrt
2 3 1
2 3 1 1
3 11 8
3 11 8 2
11 19 8
11 19 8 2
19 83 64
19 83 64 4
83 1811 1728
83 1811 1728 12
1811 2027 216
1811 2027 216 6
2027 2243 216
2027 2243 216 6
2243 2251 8
2243 2251 8 2
2251 2467 216
2251 2467 216 6
2467 2531 64
2467 2531 64 4
2531 2539 8
2531 2539 8 2
2539 3539 1000
2539 3539 1000 10
3539 3547 8
3539 3547 8 2
3547 4547 1000
3547 4547 1000 10
4547 5059 512
4547 5059 512 8
5059 10891 5832
5059 10891 5832 18
10891 12619 1728
10891 12619 1728 12
12619 13619 1000
12619 13619 1000 10
13619 13627 8
13619 13627 8 2
13627 13691 64
13627 13691 64 4
13691 13907 216
13691 13907 216 6
13907 14419 512
13907 14419 512 8
Found 23 of the smallest primes < 15,000 such that the difference of successive terma are the smallest cubic numbers
Found 23 of the smallest primes < 15,000 such that the difference of successive terma are the smallest cubic numbers
done...
done...

Revision as of 11:06, 29 March 2021

Cubic special primes is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
Task

n   is smallest prime such that the difference of successive terms are the smallest cubics of positive integers, where     n   <   15000.

Go

Translation of: Wren

<lang go>package main

import (

   "fmt"
   "math"

)

func sieve(limit int) []bool {

   limit++
   // True denotes composite, false denotes prime.
   c := make([]bool, limit) // all false by default
   c[0] = true
   c[1] = true
   // no need to bother with even numbers over 2 for this task
   p := 3 // Start from 3.
   for {
       p2 := p * p
       if p2 >= limit {
           break
       }
       for i := p2; i < limit; i += 2 * p {
           c[i] = true
       }
       for {
           p += 2
           if !c[p] {
               break
           }
       }
   }
   return c

}

func isCube(n int) bool {

   s := int(math.Cbrt(float64(n)))
   return s*s*s == n

}

func commas(n int) string {

   s := fmt.Sprintf("%d", n)
   if n < 0 {
       s = s[1:]
   }
   le := len(s)
   for i := le - 3; i >= 1; i -= 3 {
       s = s[0:i] + "," + s[i:]
   }
   if n >= 0 {
       return s
   }
   return "-" + s

}

func main() {

   c := sieve(14999)
   fmt.Println("Cubic special primes under 15,000:")
   fmt.Println(" Prime1  Prime2    Gap  Cbrt")
   lastCubicSpecial := 3
   gap := 1
   count := 1
   fmt.Printf("%7d %7d %6d %4d\n", 2, 3, 1, 1)
   for i := 5; i < 15000; i += 2 {
       if c[i] {
           continue
       }
       gap = i - lastCubicSpecial
       if isCube(gap) {
           cbrt := int(math.Cbrt(float64(gap)))
           fmt.Printf("%7s %7s %6s %4d\n", commas(lastCubicSpecial), commas(i), commas(gap), cbrt)
           lastCubicSpecial = i
           count++
       }
   }
   fmt.Println("\n", count+1, "such primes found.")

}</lang>

Output:
Same as Wren example.

Raku

A two character difference from the Quadrat Special Primes entry. (And it could have been one.) <lang perl6>my @sqp = 2, -> $previous {

   my $next;
   for (1..∞).map: *³ {
       $next = $previous + $_;
       last if $next.is-prime;
   }
   $next

} … *;

say "{+$_} matching numbers:\n", $_».fmt('%5d').batch(7).join: "\n" given

   @sqp[^(@sqp.first: * > 15000, :k)];</lang>
Output:
23 matching numbers:
    2     3    11    19    83  1811  2027
 2243  2251  2467  2531  2539  3539  3547
 4547  5059 10891 12619 13619 13627 13691
13907 14419

Ring

<lang ring> load "stdlib.ring"

see "working..." + nl

Primes = [] limit1 = 50 oldPrime = 2 add(Primes,2)

for n = 1 to limit1

   nextPrime = oldPrime + pow(n,3)
   if isprime(nextPrime)
      n = 1
      add(Primes,nextPrime)
      oldPrime = nextPrime
   else
      nextPrime = nextPrime - oldPrime
   ok

next

see "prime1 prime2 Gap Cbrt" + nl for n = 1 to Len(Primes)-1

   diff = Primes[n+1] - Primes[n]
   for m = 1 to diff
       if pow(m,3) = diff
          cbrt = m
          exit
       ok
   next
   see ""+ Primes[n] + "      " + Primes[n+1] + "    " + diff + "     " + cbrt + nl

next

see "Found " + Len(Primes) + " of the smallest primes < 15,000 such that the difference of successive terma are the smallest cubic numbers" + nl

see "done..." + nl </lang>

Output:
working...
prime1 prime2 Gap Cbrt
2      3    1     1
3      11    8     2
11      19    8     2
19      83    64     4
83      1811    1728     12
1811      2027    216     6
2027      2243    216     6
2243      2251    8     2
2251      2467    216     6
2467      2531    64     4
2531      2539    8     2
2539      3539    1000     10
3539      3547    8     2
3547      4547    1000     10
4547      5059    512     8
5059      10891    5832     18
10891      12619    1728     12
12619      13619    1000     10
13619      13627    8     2
13627      13691    64     4
13691      13907    216     6
13907      14419    512     8
Found 23 of the smallest primes < 15,000  such that the difference of successive terma are the smallest cubic numbers
done...

Wren

Library: Wren-math
Library: Wren-fmt

<lang ecmascript>import "/math" for Int, Math import "/fmt" for Fmt

var isCube = Fn.new { |n|

   var c = Math.cbrt(n).round
   return c*c*c == n

}

var primes = Int.primeSieve(14999) System.print("Cubic special primes under 15,000:") System.print(" Prime1 Prime2 Gap Cbrt") var lastCubicSpecial = 3 var gap = 1 var count = 1 Fmt.print("$,7d $,7d $,6d $4d", 2, 3, 1, 1) for (p in primes.skip(2)) {

   gap = p - lastCubicSpecial
   if (isCube.call(gap)) {
       Fmt.print("$,7d $,7d $,6d $4d", lastCubicSpecial, p, gap, Math.cbrt(gap).round)
       lastCubicSpecial = p
       count = count + 1
   }

} System.print("\n%(count+1) such primes found.")</lang>

Output:
Cubic special primes under 15,000:
 Prime1  Prime2    Gap  Cbrt
      2       3      1    1
      3      11      8    2
     11      19      8    2
     19      83     64    4
     83   1,811  1,728   12
  1,811   2,027    216    6
  2,027   2,243    216    6
  2,243   2,251      8    2
  2,251   2,467    216    6
  2,467   2,531     64    4
  2,531   2,539      8    2
  2,539   3,539  1,000   10
  3,539   3,547      8    2
  3,547   4,547  1,000   10
  4,547   5,059    512    8
  5,059  10,891  5,832   18
 10,891  12,619  1,728   12
 12,619  13,619  1,000   10
 13,619  13,627      8    2
 13,627  13,691     64    4
 13,691  13,907    216    6
 13,907  14,419    512    8

23 such primes found.