Coprime triplets

Coprime triplets is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Task

Find and show the smallest number which is coprime to the last two predecessors and has not yet appeared; a(1)=1, a(2)=2.
p and q are coprimes if they have no common factors other than 1.
Let p, q < 50

FreeBASIC

<lang freebasic>function gcd( a as uinteger, b as uinteger ) as uinteger

   if b = 0 then return a
   return gcd( b, a mod b )

end function

function num_in_array( array() as integer, num as integer ) as boolean

   for i as uinteger = 1 to ubound(array)
       if array(i) = num then return true
   next i
   return false

end function

redim as integer trips(1 to 2) trips(1) = 1 : trips(2) = 2 dim as integer last

do

   last = ubound(trips)
   for q as integer = 1 to 49
       if not num_in_array( trips(), q ) _
         andalso gcd(q, trips(last)) = 1 _
         andalso gcd(q, trips(last-1)) = 1 then
           redim preserve as integer trips( 1 to last+1 )
           trips(last+1) = q
           continue do 
       end if
   next q
   exit do

loop

print using "Found ## terms:"; ubound(trips)

for i as integer = 1 to last

   print trips(i);" ";

next i : print</lang>

Output:

Found 36 terms:
1  2  3  5  4  7  9  8  11  13  6  17  19  10  21  23  16  15  29  14  25  27  22  31  35  12  37  41  18  43  47  20  33  49  26  45

Phix

function coprime_triplets(integer less_than=50)
    sequence cpt = {1,2}
    while true do
        integer m = 1
        while find(m,cpt) 
           or gcd(m,cpt[$])!=1
           or gcd(m,cpt[$-1])!=1 do
            m += 1
        end while
        if m>=less_than then exit end if
        cpt &= m
    end while
    return cpt
end function
sequence res = apply(true,sprintf,{{"%2d"},coprime_triplets()})
printf(1,"Found %d coprime triplets:\n%s\n",{length(res),join_by(res,1,10," ")})

Output:

Found 36 coprime triplets:
 1  2  3  5  4  7  9  8 11 13
 6 17 19 10 21 23 16 15 29 14
25 27 22 31 35 12 37 41 18 43
47 20 33 49 26 45

Ring

<lang ring> see "working..." + nl row = 2 numbers = 1:50 first = 1 second = 2 see "Coprime triplets are:" + nl see "" + first + " " + second + " "

    for n = 3 to len(numbers)
        flag1 = 1
        flag2 = 1
        if first < numbers[n]
           min = first
        else
           min = numbers[n]
        ok
        for m = 2 to min
            if first%m = 0 and numbers[n]%m = 0
               flag1 = 0
               exit
            ok
        next
        if second < numbers[n]
           min = second
        else
           min = numbers[n]
        ok
        for m = 2 to min
            if second%m = 0 and numbers[n]%m = 0 
               flag2 = 0
               exit
            ok
        next
        if flag1 = 1 and flag2 = 1
           see "" + numbers[n] + " "
           first = second 
           second = numbers[n] 
           del(numbers,n)
           row = row+1
           if row%10 = 0
              see nl
           ok
           n = 2
        ok
   next

   see nl + "Found " + row + " coprime triplets" + nl
   see "done..." + nl

</lang>

Output:

working...
Coprime triplets are:
1 2 3 5 4 7 9 8 11 13 
6 17 19 10 21 23 16 15 29 14 
25 27 22 31 35 12 37 41 18 43 
47 20 33 49 26 45 
Found 36 coprime triplets
done...

Wren

Translation of: Phix

Library: Wren-math

Library: Wren-seq

Library: Wren-fmt

<lang ecmascript>import "/math" for Int import "/seq" for Lst import "/fmt" for Fmt

var limit = 50 var cpt = [1, 2]

while (true) {

   var m = 1
   while (cpt.contains(m) || Int.gcd(m, cpt[-1]) != 1 || Int.gcd(m, cpt[-2]) != 1) {
       m = m + 1
   }
   if (m >= limit) break
   cpt.add(m)

} System.print("Coprime triplets under %(limit):") for (chunk in Lst.chunks(cpt, 10)) Fmt.print("$2d", chunk) System.print("\nFound %(cpt.count) such numbers.")</lang>

Output:

Coprime triplets under 50:
 1  2  3  5  4  7  9  8 11 13
 6 17 19 10 21 23 16 15 29 14
25 27 22 31 35 12 37 41 18 43
47 20 33 49 26 45

Found 36 such numbers.