Concurrent computing: Difference between revisions
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=={{header|Java}}==
Create a new <code>Thread</code> array, shuffle the array, start each thread.
<syntaxhighlight lang="java">
Thread[] threads = new Thread[3];
threads[0] = new Thread(() -> System.out.println("enjoy"));
threads[1] = new Thread(() -> System.out.println("rosetta"));
threads[2] = new Thread(() -> System.out.println("code"));
Collections.shuffle(Arrays.asList(threads));
for (Thread thread : threads)
thread.start();
</syntaxhighlight>
<br />
An alternate demonstration
{{works with|Java|1.5+}}
Uses CyclicBarrier to force all threads to wait until they're at the same point before executing the println, increasing the odds they'll print in a different order (otherwise, while the they may be executing in parallel, the threads are started sequentially and with such a short run-time, will usually output sequentially as well).
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