Benford's law: Difference between revisions

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abs((f / double(N)) - expected[i]) * 100);
abs((f / double(N)) - expected[i]) * 100);
}</lang>
}</lang>
=={{header|Delphi}}==

See [https://rosettacode.org/wiki/Benford%27s_law#Pascal Pascal].
=={{header|Elixir}}==
=={{header|Elixir}}==
<lang elixir>defmodule Benfords_law do
<lang elixir>defmodule Benfords_law do
Retrieved from "https://rosettacode.org/wiki/Benford%27s_law"