Abundant odd numbers: Difference between revisions

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=={{header|Frink}}==
<lang frink>isAbundantOdd[n] := sum[allFactors[n, true, false]] > n
<lang frink>
/** This is a solver for the Rosetta Code problem "Abundant odd numbers"
 
https://rosettacode.org/wiki/Abundant_odd_numbers
*/
 
isAbundantOdd[n] := sum[allFactors[n, true, false]] > n
 
n = 3
490

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