Abundant odd numbers: Difference between revisions

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| [., $sum] ;</lang>
 
Computing the 10^9first abundant number greater than 10^9 is presently impractical using jq, but for the other tasks:
<lang>( ["n", "sum of divisors"],
limit(25; abundant_odd_numbers)),
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The 1000th abundant odd number and corresponding sum of divisors: 492975 1012336
</pre>
 
 
=={{header|Julia}}==
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