ABC problem: Difference between revisions

 

;Example:

True

>>> can_make_word("BARK")

True

>>> can_make_word("CONFUSE")

 

{{Template:Strings}}

=={{header|11l}}==

{{trans|Python}}

I word == ‘’

R 0B

R 1B

 

 

=={{header|360 Assembly}}==

The program uses one ASSIST macro (XPRNT) to keep the code as short as possible.

ABC CSECT

USING ABC,R13 base register

YREGS

NN EQU (BLOCKS-WORDS)/L'WORDS number of words

{{out}}

<pre>

 

=={{header|8080 Assembly}}==

jmp test

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;

wrdcommon: db 'COMMON$'

wrdsquad: db 'SQUAD$'

 

{{out}}

{{trans|8080 Assembly}}

 

bits 16

org 100h

.cmn: db 'COMMON$'

.squad: db 'SQUAD$'

 

{{out}}

 

=={{header|8th}}==

\ ========================================================================================

\ You are given a collection of ABC blocks

bye

;

=={{header|AArch64 Assembly}}==

{{works with|as|Raspberry Pi 3B version Buster 64 bits}}

/* ARM assembly AARCH64 Raspberry PI 3B */

/* program problemABC64.s */

/* for this file see task include a file in language AArch64 assembly */

.include "../includeARM64.inc"

{{Output}}

<pre>

</pre>

=={{header|ABAP}}==

REPORT z_rosetta_abc.

 

WRITE:/ COND string( WHEN word_maker=>can_make_word( word = 'SQUAD' letter_blocks = blocks ) = abap_true THEN 'True' ELSE 'False' ).

WRITE:/ COND string( WHEN word_maker=>can_make_word( word = 'CONFUSE' letter_blocks = blocks ) = abap_true THEN 'True' ELSE 'False' ).

{{out}}

<pre>

 

=={{header|Action!}}==

CHAR ARRAY sideA="BXDCNGRTQFJHVAOEFLPZ"

CHAR ARRAY sideB="OKQPATEGDSWUINBRSYCM"

Test("SQuaD")

Test("CoNfUsE")

{{out}}

[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/ABC_problem.png Screenshot from Atari 8-bit computer]

Using #HASH-OFF

</pre>

FUNCTION bCAN_MAKE_WORD(zWord: STRING): BOOLEAN

VAR sBlockCount: SHORT

RETURN OCCURS(zUsedBlocks, ",") = sWordLength

ENDFUNCTION

{{out}}

<pre>

</pre>

 

use Ada.Characters.Handling;

 

end loop;

end Abc_Problem;

 

{{out}}

=={{header|ALGOL 68}}==

{{works with|ALGOL 68G|Any - tested with release 2.8.win32}}

 

# construct the list of blocks #

 

)

Output:

<pre>

 

=={{header|ALGOL W}}==

begin

% Returns true if we can spell the word using the blocks, %

testCanSpell( "confuse", 7 )

end

{{out}}

<pre>

 

=={{header|Apex}}==

if (String.isEmpty(word)) {

return true;

System.debug('"COMMON": ' + canMakeWord(blocks, 'COMMON'));

System.debug('"SQuAd": ' + canMakeWord(blocks, 'SQuAd'));

{{out}}

<pre>"": true

=={{header|APL}}==

{{works with|Dyalog APL|16.0}}

{{out}}

<pre> )COPY dfns ucase

=={{header|AppleScript}}==

===Imperative===

"jw", "hu", "vi", "an", "ob", "er", "fs", "ly", "pc", "zm"}

 

end repeat

return false

 

===Functional===

use framework "Foundation"

 

set my text item delimiters to dlm

s

{{Out}}

<pre> '' -> true

=={{header|ARM Assembly}}==

{{works with|as|Raspberry Pi}}

/* ARM assembly Raspberry PI */

/* program problemABC.s */

/***************************************************/

.include "../affichage.inc"

<pre>

Can_make_word: A

=={{header|Arturo}}==

 

[B O] [X K] [D Q] [C P] [N A] [G T] [R E]

[T G] [Q D] [F S] [J W] [H U] [V I] [A N]

 

loop ["A" "BaRk" "bOoK" "tReAt" "CoMmOn" "SqUaD" "cONfUsE"] 'wrd

{{Out}}

<pre>A => true

 

=={{header|Astro}}==

if ls.isempty:

return true

 

for s in test:

 

=={{header|AutoHotkey}}==

 

'''Function'''

o := {}

loop, parse, blocks, `n, `r

added := 1

}

 

'''Test Input''' (as per question)

(

BO

loop, parse, wordlist, `n

out .= A_LoopField " - " isWordPossible(blocks, A_LoopField) "`n"

 

{{out}}

 

=={{header|BaCon}}==

 

DATA "A", "BARK", "BOOK", "TREAT", "Common", "Squad", "Confuse"

 

PRINT word$, IIF$(LEN(word$) = count-AMOUNT(block$), "True", "False") FORMAT "%-10s: %s\n"

{{out}}

<pre>

=={{header|BASIC}}==

Works with:VB-DOS, QB64, QBasic, QuickBASIC

' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' '

' ABC_Problem '

 

END FUNCTION

 

==={{header|Commodore BASIC}}===

{{trans|Sinclair ZX-81 BASIC}}

20 W$ = "BARK" : GOSUB 100

30 W$ = "BOOK" : GOSUB 100

230 RETURN

240 PRINT W$" -> NO"

 

{{out}}

The above greedy algorithm works on the sample data, but fails on other data - for example, it will declare that you cannot spell the word ABBA using the blocks (AB),(AB),(AC),(AC), because it will use the two AB blocks for the first two letters "AB", leaving none for the second "B". This recursive solution is more thorough about confirming negatives and handles that case correctly:

 

110 MS=100:REM MAX STACK DEPTH

120 DIM BL$(MS):REM BLOCKS LEFT

470 DATA A, BORK, BOOK, TREAT, COMMON, SQUAD, CONFUSE, ""

480 DATA ABABACAC,ABBA,""

 

{{Out}}

==={{header|Sinclair ZX81 BASIC}}===

Works with 1k of RAM. A nice unstructured algorithm. Unfortunately the requirement that it be case-insensitive is moot, because the ZX81 does not support lower-case letters.

20 INPUT W$

30 FOR I=1 TO LEN W$

90 STOP

100 NEXT J

{{in}}

<pre>A</pre>

 

=={{header|Batch File}}==

@echo off

::abc.bat

 

:END

 

=={{header|BBC BASIC}}==

{{works with|BBC BASIC for Windows}}

PROCcan_make_word("A")

PROCcan_make_word("BARK")

ENDWHILE

IF word$>"" PRINT "False" ELSE PRINT "True"

 

{{out}}

 

=={{header|BCPL}}==

 

let canMakeWord(word) = valof

show("SQUAD")

show("CONFUSE")

{{out}}

<pre>A: yes

 

=={{header|BQN}}==

Matches ← ⊑⊸(⊑∘∊¨)˜ /⊣ # blocks matching current letter

Others ← <˘∘⍉∘(»⊸≥∨`)∘(≡⌜)/¨<∘⊣ # blocks without current matches

words←⟨"A","bark","BOOK","TrEaT","Common","Squad","Confuse"⟩

 

{{out}}

<pre>┌─

 

=={{header|Bracmat}}==

( can-make-word

= ABC blocks

& can-make-word'SQUAD

& can-make-word'CONFUSE

{{out}}

<pre>A yes

=={{header|C}}==

Recursive solution. Empty string returns true.

#include <ctype.h>

 

 

return 0;

{{out}}

<pre>

This Method uses regular expressions to do the checking. Given that n = length of blocks string and

m = length of word string, then CheckWord's time complexity comes out to about m*(n - (m-1)/2).

using System.IO;

// Needed for the method.

return true;

}

{{out}}

<pre>

</pre>

'''Unoptimized'''

using System.Linq;

 

}

}

{{out}}

<pre>

{{Works with|C++11}}

Build with:

#include <vector>

#include <string>

std::cout << w << ": " << std::boolalpha << can_make_word(w,vals) << ".\n";

}

 

{{out}}

<b>module.ceylon</b>

 

module rosetta.abc "1.0.0" {}

 

<b>run.ceylon</b>

 

shared void run() {

printAndCanMakeWord("A", blocks);

myRemainingLetterIndexes)

else false;

 

{{out}}

=={{header|Clojure}}==

A translation of the Haskell solution.

(def blocks

(-> "BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM" (.split " ") vec))

(doseq [word ["A" "BARK" "Book" "treat" "COMMON" "SQUAD" "CONFUSE"]]

 

{{out}}

 

=={{header|CLU}}==

rslt: array[char] := array[char]$predict(1,string$size(s))

for c: char in string$chars(s) do

end

end

{{out}}

<pre>A: yes

 

=={{header|CoffeeScript}}==

 

canMakeWord = (word="") ->

# Expect true, true, false, true, false, true, true, true

for word in ["A", "BARK", "BOOK", "TREAT", "COMMON", "squad", "CONFUSE", "STORM"]

 

{{out}}

 

=={{header|Comal}}==

0020 blocks$:=" BOXKDQCPNAGTRETGQDFSJWHUVIANOBERFSLYPCZM"

0030 FOR i#:=1 TO LEN(word$) DO

0170 END

0180 //

{{out}}

<pre>A: yes

 

=={{header|Common Lisp}}==

(defun word-possible-p (word blocks)

(cond

collect (word-possible-p

(subseq word 1)

 

{{out}}

=={{header|Component Pascal}}==

{{Works with|BlackBox Component Builder}}

MODULE ABCProblem;

IMPORT

END ABCProblem.

Execute: ^Q ABCProblem.CanMakeWord A BARK BOOK TREAT COMMON SQUAD confuse~

{{out}}

 

=={{header|Cowgol}}==

include "strings.coh";

 

print(resp[can_make_word(words[i])]);

i := i + 1;

 

{{out}}

{{trans|Python}}

A simple greedy algorithm is enough for the given sequence of blocks. canMakeWord is true on an empty word because you can compose it using zero blocks.

 

bool canMakeWord(in string word, in string[] blocks) pure /*nothrow*/ @safe {

foreach (word; "" ~ "A BARK BoOK TrEAT COmMoN SQUAD conFUsE".split)

writefln(`"%s" %s`, word, canMakeWord(word, blocks));

{{out}}

<pre>"" true

===@nogc Version===

The same as the precedent version, but it avoids all heap allocations and it's lower-level and ASCII-only.

 

bool canMakeWord(in string word, in string[] blocks) nothrow @nogc

foreach (word; "" ~ "A BARK BoOK TrEAT COmMoN SQUAD conFUsE".split)

writefln(`"%s" %s`, word, canMakeWord(word, blocks));

 

===Recursive Version===

This version is able to find the solution for the word "abba" given the blocks AB AB AC AC.

{{trans|C}}

 

alias Block = char[2];

immutable word = "abba";

writefln(`"%s" %s`, word, blocks2.canMakeWord(word));

{{out}}

<pre>"" true

===Alternative Recursive Version===

This version doesn't shuffle the input blocks, but it's more complex and it allocates an array of indexes.

 

alias Block = char[2];

immutable word = "abba";

writefln(`"%s" %s`, word, blocks2.canMakeWord(word));

The output is the same.

 

=={{header|Delphi}}==

Just to be different I implemented a block as a set of (2) char rather than as an array of (2) char.

{$APPTYPE CONSOLE}

 

readln;

end.

 

{{out}}

 

=={{header|Draco}}==

 

proc nonrec ucase(char c) char:

test("sQuAd");

test("CONFUSE")

{{out}}

<pre>A: yes

{{trans|Swift}}

 

var blocks = [

"BO", "XK", "DQ", "CP", "NA", "GT", "RE", "TG", "QD", "FS",

for str in [ "A", "BARK", "BooK", "TrEaT", "comMON", "sQuAd", "Confuse" ] {

print("\"\(str)\" \(canOrNot(blockable(str))) be spelled with blocks.")

 

{{out}}

 

=={{header|EchoLisp}}==

(lib 'list) ;; list-delete

 

(spell (string-rest word) (list-delete blocks block))))))

{{out}}

<pre>

=={{header|Ela}}==

{{trans|Haskell}}

 

:::IO

 

mapM_ (\w -> putLn (w, not << null $ abc blocks (map char.upper w)))

 

{{out}}

=={{header|Elena}}==

ELENA 5.0

import system'collections;

import extensions;

console.printLine("can make '",word,"' : ",word.canMakeWordFrom(blocks));

}

{{out}}

<pre>

{{trans|Erlang}}

{{works with|Elixir|1.3}}

def can_make_word(word, avail) do

can_make_word(String.upcase(word) |> to_charlist, avail, [])

blocks = ~w(BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM)c

~w(A Bark Book Treat Common Squad Confuse) |>

 

{{out}}

 

=={{header|Erlang}}==

-export([can_make_word/1, can_make_word/2, blocks/0]).

 

main(_) -> lists:map(fun(W) -> io:fwrite("~s: ~s~n", [W, can_make_word(W)]) end,

["A","Bark","Book","Treat","Common","Squad","Confuse"]).

 

{{Out}}

 

=={{header|ERRE}}==

PROGRAM BLOCKS

 

CANMAKEWORD("Confuse")

END PROGRAM

 

=={{header|Euphoria}}==

implemented using OpenEuphoria

include std/text.e

 

 

if getc(0) then end if

{{out}}

<pre>

=={{header|F_Sharp|F#}}==

<p>This solution does not depend on the order of the blocks, neither on the symmetry of blocks we see in the example block set. (Symmetry: if AB is a block, an A comes only with another AB|BA)</p>

let rec look_for_right_candidate candidates noCandidates c rest =

match candidates with

 

List.iter (fun w -> printfn "Using the blocks we can make the word '%s': %b" w (spell_word_with blocks w)) words

{{out}}

<pre>h:\RosettaCode\ABC\Fsharp>RosettaCode "BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM" a bark book threat common squad confuse

 

=={{header|Factor}}==

kernel math math.statistics qw sequences sets unicode ;

IN: rosetta-code.abc-problem

show-blocks header input [ result ] each ;

 

{{out}}

<pre>

=={{header|FBSL}}==

This approach uses a string, blanking out the pair previously found. Probably faster than array manipulation.

#APPTYPE CONSOLE

SUB MAIN()

RETURN TRUE

END FUNCTION

{{out}}

<pre>

{{works with|gforth|0.7.3}}

 

variable blocks

: allotblocks ( -- ) here blockslist dup allot here over - swap move blocks ! ;

;

 

 

{{out}}

=={{header|Fortran}}==

Attempts to write the word read from unit 5. Please find the output, bash command, and gfortran compilation instructions as commentary at the start of the source, which starts right away!

!Compilation started at Thu Jun 5 01:52:03

!

end subroutine ucase

 

 

===But if backtracking might be needed===

 

The following source begins with some support routines. Subroutine PLAY inspects the collection of blocks to make various remarks, and function CANBLOCK reports on whether a word can be spelled out with the supplied blocks. The source requires only a few of the F90 features. The MODULE protocol eases communication, but the key feature is that subprograms can now declare arrays of a size determined on entry via parameters. Previously, a constant with the largest-possible size would be required.

MODULE PLAYPEN !Messes with a set of alphabet blocks.

INTEGER MSG !Output unit number.

END DO

END

Output: the first column of T/F is the report from CANBLOCK, the second is the expected answer from the example, and the third is whether the two are in agreement.

<pre>

 

=={{header|FreeBASIC}}==

' compile with: fbc -s console

 

Print : Print "hit any key to end program"

Sleep

{{out}}

<pre>A true

 

=={{header|FutureBasic}}==

include "NSLog.incl"

 

 

HandleEvents

{{output}}

<pre>

=={{header|Gambas}}==

'''[https://gambas-playground.proko.eu/?gist=ae860292d4588b3627d77c85bcc634ee Click this link to run this code]'''

Dim sCheck As String[] = ["A", "BARK", "BOOK", "TREAT", "COMMON", "SQUAD", "CONFUSE"]

Dim sBlock As String[] = ["BO", "XK", "DQ", "CP", "NA", "GT", "RE", "TG", "QD", "FS", "JW", "HU", "VI", "AN", "OB", "ER", "FS", "LY", "PC", "ZM"]

Next

 

Output:

<pre>

 

=={{header|Go}}==

 

import (

fmt.Println(word, sp(word))

}

{{out}}

<pre>

=={{header|Groovy}}==

Solution:

def blocks

 

word.every { letter -> blocksLeft.remove(blocksLeft.find { block -> block.contains(letter) }) }

}

 

Test:

"JW", "HU", "VI", "AN", "OB", "ER", "FS", "LY", "PC", "ZM"])

 

['', 'A', 'BARK', 'book', 'treat', 'COMMON', 'SQuAd', 'CONFUSE'].each {

println "'${it}': ${a.canMakeWord(it)}"

 

{{out}}

=={{header|Harbour}}==

Harbour Project implements a cross-platform Clipper/xBase compiler.

 

LOCAL cStr

NEXT

 

{{out}}

<pre>

 

The following function returns a list of all the solutions. Since Haskell is lazy, testing whether the list is null will only do the minimal amount of work necessary to determine whether a solution exists.

import Data.Char (toUpper)

 

main :: IO ()

main = mapM_ (\w -> print (w, not . null $ abc blocks (map toUpper w)))

 

{{out}}

Or, in terms of the bind operator:

 

import Data.List (delete)

 

words $

"BO XK DQ CP NA GT RE TG QD FS JW"

{{Out}}

<pre>("",True)

 

Works in both languages:

blocks := ["bo","xk","dq","cp","na","gt","re","tg","qd","fs",

"jw","hu","vi","an","ob","er","fs","ly","pc","zm",&null]

}

}

 

Sample run:

=={{header|J}}==

'''Solution:'''

'rows cols'=. i.&.> $y

for_c. cols do.

)

 

'''Examples:'''

ExampleWords=: <;._2 'A BaRK BOoK tREaT COmMOn SqUAD CoNfuSE '

 

"COmMOn" F

"SqUAD" T

 

'''Tacit version'''

uppc=:(-32*96&<*.123&>)&.(3&u:)

reduc=: ] delElem 1 i.~e."0 1

 

{{out}}

Another approach might be:

 

ExampleWords=: ;: 'A BaRK BOoK tREaT COmMOn SqUAD CoNfuSE '

 

candidates=: word,"1>,{{relevant

+./(((#need){. #/.~)"1 candidates) */ .>:need

 

Example use:

 

1

Blocks canform 1{::ExampleWords

1

Blocks canform 6{::ExampleWords

 

Explanation:

For example:

 

1

word

ANN

AAA

 

Here, the word is simply 'A', and we have two blocks to consider for our word: AN and NA. So we form all possible combinations of the letters of those two bocks, prefix each of them with our word and test whether any of them contain two copies of the letters of our word. (As it happens, three of the candidates are valid, for this trivial example.)

{{trans|C}}

{{works with|Java|1.6+}}

import java.util.Collections;

import java.util.List;

return false;

}

{{out}}

<pre>"": true

====Imperative====

The following method uses regular expressions and the string replace function to allow more support for older browsers.

 

function CheckWord(blocks, word) {

for(var i = 0;i<words.length;++i)

console.log(words[i] + ": " + CheckWord(blocks, words[i]));

 

Result:

 

====Functional====

 

var strBlocks =

return strWords.split(' ').map(solution).join('\n');

 

{{Out}}

bark -> BO NA RE XK

BooK: [no solution]

COMMON: [no solution]

squAD -> FS DQ HU NA QD

 

===ES6===

====Imperative====

let blocks = characters.split(" ").map(pair => pair.split(""));

"CONFUSE"

].forEach(word => console.log(`${word}: ${isWordPossible(word)}`));

 

Result:

====Functional====

{{Trans|Haskell}}

"use strict";

 

// MAIN ---

return main();

{{Out}}

<pre>["",true]

 

=={{header|jq}}==

# when_index(cond;ary) returns the index of the first element in ary

# that satisfies cond; it uses a helper function that takes advantage

else .[1:] | abc($blks)

end

["BO","XK","DQ","CP","NA","GT","RE","TG","QD","FS",

"JW","HU","VI","AN","OB","ER","FS","LY","PC","ZM"] as $blocks

| ("A", "BARK","BOOK","TREAT","COMMON","SQUAD","CONFUSE")

{{Out}}

A : true

=={{header|Jsish}}==

Based on Javascript ES5 imperative solution.

/* ABC problem, in Jsish. Can word be spelled with the given letter blocks. */

var blocks = "BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM";

can spell CONFUSE

=!EXPECTEND!=

 

{{out}}

 

=={{header|Julia}}==

 

function abc(str::AbstractString, list)

@printf("%-8s | %s\n", str, abc(str, list))

end

 

{{out}}

=={{header|Kotlin}}==

{{trans|Java}}

fun run() {

println("\"\": " + blocks.canMakeWord(""))

}

 

{{out}}

<pre>"": true

=={{header|Liberty BASIC}}==

===Recursive solution===

print "Rosetta Code - ABC problem (recursive solution)"

print

wend

end function

{{out}}

<pre>

</pre>

===Procedural solution===

print "Rosetta Code - ABC problem (procedural solution)"

print

LetterOK=1

end sub

{{out}}

<pre>

 

=={{header|Logo}}==

[J W] [H U] [V I] [A N] [O B] [E R] [F S] [L Y] [P C] [Z M]]

 

]

 

 

{{Out}}

 

=={{header|Lua}}==

{"B","O"}; {"X","K"}; {"D","Q"}; {"C","P"};

{"N","A"}; {"G","T"}; {"R","E"}; {"T","G"};

end

print(found)

 

{{Output}}

 

 

Module ABC {

can_make_word("A")

}

ABC

 

{{out}}

 

=={{header|Maple}}==

local blocks, i, j, word, letterFound;

blocks := Array([["B", "O"], ["X", "K"], ["D", "Q"], ["C", "P"], ["N", "A"], ["G", "T"], ["R", "E"], ["T", "G"],

end proc:

 

{{out}}

<pre>

 

=={{header|Mathematica}} / {{header|Wolfram Language}}==

blocks=Partition[Characters[ToLowerCase["BOXKDQCPNAGTRETGQDFSJWHUVIANOBERFSLYPCZM"]],2];

ClearAll[DoStep,ABCBlockQ]

DoStep[opts_List]:=Flatten[DoStep@@@opts,1]

ABCBlockQ[str_String]:=(FixedPoint[DoStep,{{Characters[ToLowerCase[str]],blocks,{}}}]=!={})

{{Out}}

<pre>

 

=={{header|MATLAB}} / {{header|Octave}}==

combos = ['BO' ; 'XK' ; 'DQ' ; 'CP' ; 'NA' ; 'GT' ; 'RE' ; 'TG' ; 'QD' ; ...

'FS' ; 'JW' ; 'HU' ; 'VI' ; 'AN' ; 'OB' ; 'ER' ; 'FS' ; 'LY' ; ...

k = k+1;

end

{{out}}

<pre>Can make word A.

Recursively checks if the word is possible if a block is removed from the array.

 

-- This is the blocks array

global GlobalBlocks = #("BO","XK","DQ","CP","NA", \

)

)

 

'''Output:'''

iswordpossible "a"

true

iswordpossible "confuse"

true

 

 

=== Non-recursive ===

fn isWordPossible2 word =

(

) else return false

)

 

Both versions are good for this example, but the non-recursive version won't work if the blocks are more random, because it just takes the first found block, and the recursive version decides which one to use.

Then:

 

iswordpossible "water"

true

iswordpossible2 "water"

false

 

Non-recursive version quickly decides that it's not possible, even though it clearly is.

 

=={{header|Mercury}}==

:- interface.

:- import_module io.

io.format("can_make_word(""%s"") :- %s.\n",

[s(W), s(if P then "true" else "fail")], !IO)),

 

Note that 'P', in the foldl near the end, is not a boolean variable, but a zero-arity currying of can_make_word (i.e., it's a 'lambda' that takes no arguments and then calls can_make_word with all of the already-supplied arguments).

 

=={{header|MiniScript}}==

swap = function(list, index1, index2)

print out + ": " + canMakeWord(val, allBlocks)

end for

 

=={{header|Nim}}==

{{works with|Nim|0.20.0}}

 

func canMakeWord(blocks: seq[string]; word: string): bool =

echo()

 

{{Out}}

<pre>Using the blocks BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM

=={{header|Oberon-2}}==

Works with oo2c Version 2

MODULE ABCBlocks;

IMPORT

Out.String("confuse: ");Out.Bool(CanMakeWord("confuse"));Out.Ln;

END ABCBlocks.

Output:

<pre>

=={{header|Objeck}}==

{{trans|Java}}

function : Main(args : String[]) ~ Nil {

blocks := ["BO", "XK", "DQ", "CP", "NA",

arr[j] := tmp;

}

<pre>

"": true

 

=={{header|OCaml}}==

('B', 'O'); ('X', 'K'); ('D', 'Q'); ('C', 'P');

('N', 'A'); ('G', 'T'); ('R', 'E'); ('T', 'G');

"SQUAD", true;

"CONFUSE", true;

 

{{Out}}

=={{header|Oforth}}==

 

 

["BO","XK","DQ","CP","NA","GT","RE","TG","QD","FS","JW","HU","VI","AN","OB","ER","FS","LY","PC","ZM"]

]

false

 

{{out}}

=={{header|OpenEdge/Progress}}==

 

 

/* List of blocks */

RETURN TRUE.

END FUNCTION.

 

{{out}}

 

=={{header|Order}}==

#include <order/lib.h>

 

)

 

 

{{out}}

 

=={{header|PARI/GP}}==

WORDS = ["A","Bark","BOOK","Treat","COMMON","SQUAD","conFUSE"];

 

}

 

 

Output:<pre>A 1

{{works with|Free Pascal|2.6.2}}

 

#!/usr/bin/instantfpc

//program ABCProblem;

TestABCProblem('SQUAD');

TestABCProblem('CONFUSE');

 

{{out}}

=={{header|Perl}}==

Recursive solution that can handle characters appearing on different blocks:

use warnings;

use strict;

}

return

<p>Testing:

 

my @blocks1 = qw(BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM);

my @blocks2 = qw(US TZ AO QA);

is(can_make_word('auto', @blocks2), 1);

===Regex based alternate===

 

use strict; # https://rosettacode.org/wiki/ABC_Problem

while $blocks =~ /\w?$letter\w?/gi;

return 'False';

{{out}}

<pre>

=={{header|Phix}}==

Recursive solution which also solves the extra problems on the discussion page.

<span style="color: #004080;">sequence</span> <span style="color: #000000;">blocks</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">words</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">used</span>

<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>

<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>

{{out}}

<pre>

=={{header|PHP}}==

 

<?php

$words = array("A", "BARK", "BOOK", "TREAT", "COMMON", "SQUAD", "Confuse");

echo canMakeWord($word) ? "True" : "False";

echo "\r\n";

{{out}}

<pre>

=={{header|Picat}}==

Showing both a Picat style version (check_word/2) and a Prolog style recursive version (check_word2/2). go2/0 generates all possible solutions (using fail/0) to backtrack.

test_it(check_word),

test_it(check_word2),

block(p,c).

block(z,m).

 

{{out}}

=={{header|PicoLisp}}==

Mapping and recursion.

'((B O) (X K) (D Q) (C P) (N A) (G T) (R E)

(T G) (Q D) (F S) (J W) (H U) (V I) (A N)

(println Word (abc Word *Blocks) (abcR Word *Blocks)) )

 

=={{header|PL/I}}==

===version 1===

 

declare word character (20) varying, blocks character (200) varying initial

end;

 

<pre>

A true

 

===version 2===

abc: Proc Options(main);

/* REXX --------------------------------------------------------------

End;

 

{{out}}

<pre>'$' cannot be spelt.

 

=={{header|PL/M}}==

 

/* ABC PROBLEM ON $-TERMINATED STRING */

 

CALL BDOS(0,0);

{{out}}

<pre>A: YES

Works with PowerBASIC 6 Console Compiler

 

#DIM ALL

'

END IF

END FUNCTION

{{out}}

<pre>$ FALSE

 

=={{header|PowerShell}}==

.Synopsis

ABC Problem

{

test-blocks -testword $word -Verbose

{{out}}

<pre>

Works with SWI-Prolog 6.5.3

 

maplist(abc_problem, ['', 'A', bark, bOOk, treAT, 'COmmon', sQuaD, 'CONFUSE']).

 

( select([H, _], L, L1); select([_, H], L, L1)),

can_makeword(L1, T).

{{out}}

<pre> ?- abc_problem.

{{works with|SWI Prolog 7}}

 

abathslib(protelog/composer) ]).

 

%% These rules, removing remaining constraints from the store, are just cosmetic:

'clean up blocks' @ word_built \ block(_) <=> true.

 

 

Demonstration:

 

true.

?- can_build_word("BARK").

true.

?- can_build_word("CONFUSE").

 

=={{header|PureBasic}}==

===PureBasic: Iterative===

#LETTERS = "BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM "

 

PrintN(can_make_word("SqUAD"))

PrintN(can_make_word("COnFUSE"))

 

===PureBasic: Recursive===

 

Macro test(t)

test("a") : test("BaRK") : test("BOoK") : test("TREAt")

test("cOMMON") : test("SqUAD") : test("COnFUSE")

{{out}}

<pre>a = True

 

===Python: Iterative, with tests===

'''

Note that this code is broken, e.g., it won't work when

["", "a", "baRk", "booK", "treat",

"COMMON", "squad", "Confused"]))

 

{{out}}

 

===Python: Recursive===

 

def _abc(word, blocks):

if __name__ == '__main__':

for word in [''] + 'A BARK BoOK TrEAT COmMoN SQUAD conFUsE'.split():

 

{{out}}

 

===Python: Recursive, telling how===

if not w: return []

 

 

for w in ", A, bark, book, treat, common, SQUAD, conFUsEd".split(', '):

 

{{out}}

=={{header|q}}==

The possibility of ‘backtracking’, discussed in the FORTRAN solution above (and not tested by the example set) makes this a classic tree search: wherever there is a choice of blocks from which to pick the next letter, each choice must be tested.

WORDS:string`A`BARK`BOOK`TREAT`COMMON`SQUAD`CONFUSE

 

$[0=count s; 1b; / empty string

not any found:any each b=s 0; 0b; / cannot proceed

{{out}}

The first expression tests whether the string <code>s</code> is empty. If so, the result is true. This matches two cases: either the string is empty and can be made from any set of blocks; or all its letters have been matched and there is nothing more to check.

 

 

To meet the requirement for case-insensitivity and to display the results, apply the above within a wrapper.

{{out}}

A true

bark true

COMMON false

squad true

* [https://code.kx.com/q/ref/ Language Reference]

* [https://code.kx.com/q/learn/pb/abc-problem/ The Q Playbook: ABC problem – analysis]

This solution assumes the constraint that if a letter appears on more than one block those blocks are identical (as in the example set) so backtracking is not required.

 

$ "JWHUVIANOBERFSLYPCZM"

join ] constant is blocks ( --> $ )

[ drop dip not

conclude ] ]

 

'''Testing in the Quackery shell:'''

This solution does not assume the constraint that if a letter appears on more than one block those blocks are identical (as in the example set) so backtracking is required.

 

witheach

[ over -1 peek

bailed dup

if [ dip 2drop ]

'''Testing in the Quackery shell:'''

Identical to iterative solution above.

Vectorised function for R which will take a character vector and return a logical vector of equal length with TRUE and FALSE as appropriate for words which can/cannot be made with the blocks.

 

c("X","K"),

c("D","Q"),

"COMMON",

"SQUAD",

 

{{out}}

===Without recursion===

Second version without recursion and giving every unique combination of blocks for each word:

x <- toupper(x)

charList <- strsplit(x, character(0))

"COMMON",

"SQUAD",

{{out}}

<pre>$A

So '(can-make-word? "")' is true for me.

 

(define block-strings

(list "BO" "XK" "DQ" "CP" "NA"

(check-false (can-make-word? "COMMON"))

(check-true (can-make-word? "SQUAD"))

 

{{out}}

{{works with|rakudo|6.0.c}}

Blocks are stored as precompiled regexes. We do an initial pass on the blockset to include in the list only those regexes that match somewhere in the current word. Conveniently, regexes scan the word for us.

my @regex = @blocks.map({ my @c = .comb; rx/<@c>/ }).grep: { .ACCEPTS($word.uc) }

can-spell-word $word.uc.comb.list, @regex;

for <A BaRK BOoK tREaT COmMOn SqUAD CoNfuSE> {

say "$_ &can-spell-word($_, @b)";

{{out}}

<pre>A True

 

=={{header|RapidQ}}==

dim InWord as string

 

Blocks = "BO, XK, DQ, CP, NA, GT, RE, TG, QD, FS, JW, HU, VI, AN, OB, ER, FS, LY, PC, ZM"

showmessage "Can make: " + InWord + " = " + iif(CanMakeWord(InWord, Blocks), "True", "False")

{{out}}

<pre>Can make: A = TRUE

 

=={{header|Red}}==

test: func [ s][

p: copy "BOXKDQCPNAGTRETGQDFSJWHUVIANOBERFSLYPCZM"

print reduce [ pad copy word 8 ":" test word]

]

{{out}}

<pre>

=={{header|REXX}}==

===version 1===

list= 'A bark bOOk treat common squaD conFuse' /*words can be: upper/lower/mixed case*/

blocks= 'BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM'

end /*try*/ /* [↑] end of a "TRY" permute. */

say right( arg(1), 30) right( word( "can't can", (n==L) + 1), 6) 'be spelt.'

{{out|output|text=&nbsp; when using the default inputs:}}

<pre>

 

===version 2===

* 10.01.2014 Walter Pachl counts the number of possible ways

* 12.01.2014 corrected date and output

used.w=1

End

{{out}}

<pre>'' cannot be spelt.

 

=={{header|Ring}}==

Words = [ :A, :BARK, :BOOK, :TREAT, :COMMON, :SQUAD, :CONFUSE ]

 

if found = false return false ok

next

{{Out}}

<pre>

=={{header|Ruby}}==

This one uses a case insensitive regular expression. The 'sub!' method substitutes the first substring it finds and returns nil if nothing is found.

 

words.each do |word|

puts "#{word.inspect}: #{res}"

end

{{Out}}

<pre>

 

=={{header|Run BASIC}}==

makeWord$ = "A,BARK,BOOK,TREAT,COMMON,SQUAD,Confuse"

b = int((len(blocks$) /3) + 1)

print wrd$;chr$(9);

if n = len(wrd$) then print " True" else print " False"

<pre>A True

BARK True

=={{header|Rust}}==

This implementation uses a backtracking search.

 

fn rec_can_make_word(index: usize, word: &str, blocks: &[&str], used: &mut[bool]) -> bool {

}

}

{{Out}}

<pre>

 

=={{header|Scala}}==

 

protected class Block(face1: Char, face2: Char) {

 

words.foreach(w => println(s"$w can${if (isMakeable(w, blocks)) " " else "not "}be made."))

 

=={{header|Scheme}}==

In R5RS:

'((#\B #\O) (#\X #\K) (#\D #\Q) (#\C #\P) (#\N #\A)

(#\G #\T) (#\R #\E) (#\T #\G) (#\Q #\D) (#\F #\S)

(display word)

(newline))

{{out}}

<pre>

 

=={{header|Seed7}}==

 

const func boolean: canMakeWords (in array string: blocks, in string: word) is func

writeln(word rpad 10 <& canMakeWords(word));

end for;

 

{{out}}

 

=={{header|SenseTalk}}==

 

put [

return True

 

"A",

"BARK",

]

put CanMakeWord(word)

 

=={{header|SequenceL}}==

===Recursive Search Version===

import <Utilities/Sequence.sl>;

 

letter when ascii >= 65 and ascii <= 90

else

 

{{out}}

 

===RegEx Version ===

import <Utilities/Sequence.sl>;

import <RegEx/RegEx.sl>;

letter when ascii >= 65 and ascii <= 90

else

 

=={{header|Sidef}}==

{{trans|Perl}}

 

blocks.map! { |b| b.uc.chars.sort.join }.freq!

return false;

}(word.uc.chars, blocks)

 

Tests:

var b2 = %w(US TZ AO QA)

 

say ("%7s -> %s" % (t[0], bool));

assert(bool == t[1])

 

{{out}}

 

=={{header|Simula}}==

BEGIN

 

 

END.

{{out}}

<pre>A => T OK

=={{header|Smalltalk}}==

Recursive solution. Tested in Pharo.

ABCPuzzle>>test

#('A' 'BARK' 'BOOK' 'TreaT' 'COMMON' 'sQUAD' 'CONFuSE') do: [ :each |

(self solveFor: ldash with: bdash) ifTrue: [ ^ true ] ].

^ false

{{out}}

<pre>

=={{header|SNOBOL4}}==

{{works with|SNOBOL4, SPITBOL for Linux}}

* Program: abc.sbl,

* To run: sbl -r abc.sbl

P C

Z M

{{out}}

<pre>

=={{header|SPAD}}==

{{works with|FriCAS, OpenAxiom, Axiom}}

blocks:List Tuple Symbol:= _

[(B,O),(X,K),(D,Q),(C,P),(N,A),(G,T),(R,E),(T,G),(Q,D),(F,S), _

[canMakeWord?(s,blocks) for s in Example]

 

 

Programming details:[http://fricas.github.io/book.pdf UserGuide]

 

=={{header|Standard ML}}==

val BLOCKS = [(#"B",#"O"), (#"X",#"K"), (#"D",#"Q"), (#"C",#"P"), (#"N",#"A"), (#"G",#"T"),

(#"R",#"E"), (#"T",#"G"), (#"Q",#"D"), (#"F",#"S"), (#"J",#"W"), (#"H",#"U"), (#"V",#"I"),

val words = ["A","UTAH","AutO"];

map (fn st => cando(map Char.toUpper (String.explode st),[],BLOCKS)) words;

Output

<pre>val it = [true, true, false, true, false, true, true]: bool list

 

=={{header|Swift}}==

 

func Blockable(str: String) -> Bool {

for str in [ "A", "BARK", "BooK", "TrEaT", "comMON", "sQuAd", "Confuse" ] {

println("'\(str)' \(CanOrNot(Blockable(str))) be spelled with blocks.")

{{out}}

<pre>

 

{{works with|Swift|3.0.2}}

 

func canMake(word: String) -> Bool {

let words = ["a", "bARK", "boOK", "TreAt", "CoMmon", "SquAd", "CONFUse"]

 

{{out}}

<pre>

=={{header|Tcl}}==

{{works with|Tcl|8.6}}

 

proc abc {word {blocks {BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM}}} {

foreach word {"" A BARK BOOK TREAT COMMON SQUAD CONFUSE} {

puts [format "Can we spell %9s? %s" '$word' [abc $word]]

{{out}}

<pre>

 

=={{header|TUSCRIPT}}==

set result = *

loop word = words

set out = concat (word, " ", cond)

set result = append (result, out)

{{out}}

<pre>A true

=={{header|TXR}}==

 

(defvar blocks '((B O) (X K) (D Q) (C P) (N A) (G T) (R E) (T G)

(Q D) (F S) (J W) (H U) (V I) (A N) (O B) (E R)

@(if (can-make-word w) "True" "False")

@(end)

 

Run:

This is example is a slight modification of the C and C++ examples. To avoid warning "<bold>warning: ISO C++11 does not allow conversion from string literal to 'char *' [-Wwritable-strings]</bold> the strings added to char were individually prefixed with (char*). Swap is used instead of SWAP. Return 0 was not not needed.

 

#include <Core/Core.h>

#include <stdio.h>

 

}

 

{{out}}

{{works with|bash}}

 

if [[ $1 ]]; then

can_build_word_rec "$1" BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM

can_build_word "$word" "${blocks[@]}" && ans=yes || ans=no

printf "%s\t%s\n" "$word" $ans

 

{{out}}

'''String-based solution'''

 

···

http://rosettacode.org/wiki/ABC_Problem

i: blocks.indexOf (word.substring 0, 1), i + 3

return solution

 

'''Collection-based solution'''

 

···

http://rosettacode.org/wiki/ABC_Problem

Collections.swap blocks, 0, i

return false

 

=={{header|VBA}}==

 

Option Explicit

 

ABC = (NbInit = (myColl.Count + Len(myWord)))

End Function

{{out}}

<pre>

{{trans|Go}}

{{libheader|Wren-fmt}}

 

var r // recursive

for (word in ["A", "BARK", "BOOK", "TREAT", "COMMON", "SQUAD", "CONFUSE"]) {

System.print("%(Fmt.s(-7, word)) %(sp.call(word))")

 

{{out}}

 

=={{header|XPL0}}==

 

char Side1, Side2;

Text(0, if CanMakeWord(Words(J)) then "True" else "False"); CrLf(0);

];

 

{{out}}

 

=={{header|Yabasic}}==

 

sub canMake(letters$, word$)

print "common = ", canMake(letters$, "common") // 0

print "squad = ", canMake(letters$, "squad") // 1

 

=={{header|zkl}}==

{{trans|C}}

"JW", "HU", "VI", "AN", "OB", "ER", "FS", "LY", "PC", "ZM", );

 

foreach word in (T("","A","BarK","BOOK","TREAT","COMMON","SQUAD","Confuse","abba")){

can_make_word(word).println(": ",word);

{{out}}

<pre>

 

=={{header|zonnon}}==

module Main;

type

CanMakeWord("confuse");

end Main.

{{Out}}

<pre>

 

=={{header|ZX Spectrum Basic}}==

20 READ p

30 FOR c=1 TO p

190 REM Erase pair

200 IF j/2=INT (j/2) THEN LET u$(j-1 TO j)=" ": RETURN

{{out}}

<pre>